To find the maximum value of 2x + 5y within the feasible region, you would need to evaluate the objective function at each corner point of the feasible region. The corner points are the vertices of the feasible region where the constraints intersect. Calculate the value of 2x + 5y at each corner point and identify the point where it is maximized. This point will give you the maximum value of 2x + 5y within the feasible region.
f(-2,3) = 11 f(5,-3) = -5 f(1,4) = 22, maximum
No. For 0 < x < 2, 2x is larger.
If you mean 2x = 28 then the value of x is 14
If you mean: 2x-0.04 =1.24 then the value of x works out as 0.64
The idea is to: * Replace "x" by "4" in -2x * Do the calculations * Take the absolute value
14
The answer obviously depends on what the boundaries of the feasibility region are.
2x+2y
5
f(-2,3) = 11 f(5,-3) = -5 f(1,4) = 22, maximum
sin(theta) reach a maximum at pi / 2 + all even multiple of 2 pi. As a result, the smallest positive value of x where y = sin(2x) is maximal is pi / 2.
(2x)2 = 4 x2 Its numerical value depends on the value of 'x'.
18
No. For 0 < x < 2, 2x is larger.
If you mean 2x = 28 then the value of x is 14
Do you mean "what is the value of x when 3x - 2x = 15?" in that case, the value of x is 15
If you mean: 2x-0.04 =1.24 then the value of x works out as 0.64