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The mean is (8 + 7 + 10 + 14 + 1)/5 = 8

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12y ago

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What are the 2 numbers if the arithmetic mean is 7 and the geometric mean is 3?

(x+y)/2=7; x+y=14; y=14-x 3=√(xy); xy=9; y=9/x Use substitution: 14-x=9/x; 14x - x2=9; x2 - 14x +9=0 Use the quadratic formula: x=[14±√(196-36)]/2; x=[14±√160]/2; x=[14±4√10]/2 x=7+2√10 or x=7-2√10 If x=7+2√10, then y=14-(7+2√10)=7-2√10 If x=7-2√10, then y=14-(7-2√10)=7+2√10 The first pair's geometric mean is √[(7+2√10)(7-2√10)]=√[72-(2√10)2]=√(49-40)=√9=3. The first pair's arithmetic mean is (7+2√10 +7-2√10)/2=14/2=7 The second pair's geometric mean is √[(7-2√10)(7+2√10)]=√[72-(2√10)2]=√(49-40)=√9=3. The second pair's arithmetic mean is (7-2√10 +7+2√10)/2=14/2=7 That's it!