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First we find the sum of the integers from 2 to 100 including 2 and 100, then we divide by 99 since there are 99 numbers. There are 100 numbers between 1 and 100 and we are excluding only the number 1. If we want to exclude the number 2, and count only the numbers 3,4,5....100, this can be done with the same procedure and a slight modification. So the sum of the numbers 1 to 100 can be found by writing the numbers 1, 2,3,...100 Now write them backwards, starting at 100,99,98....1 Each column has a sum of 101 and there are 100 columns. So the total is 100x101, but we wrote the list twice so we must divide by 2 The sum is 100x101/2=50x101=5050 Now remember we want only 2 to 100 so the sum we seek is 5049. Since there are 99 number, the mean is 5049/99=51 In general the sum of the first n positive integers is n(n+1)/2 This can be proved the way we did or by induction.
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How many are the first 100 positive integers are divisible by 7?
(7*100*101)/2 = 35,350 jpacs * * * * * What? How can there be 35,350 integers in the first 100 integers? There are 14 of them.
The sum of two consecutive odd integers is 100 Find the integers?
They are 2n+2
What is the pattern for the sum integers 1 to 100?
It is 100*(100+1)/2 = 50500.
How many triple digit numbers are there?
there are 999 - 100 + 1 = 900 positive triple digit positive integers, between 100 and 999.(e.g. there are 102 - 100 + 1 = 3 triple digit integers between 100 and 102,namely 100, 101 and 102.)multiply that by 2 to take in consideration of the negative integers,you have 1800 triple digit integers.
How do you write 33 hundredths as the ratio of 2 integers?
33/100 !
How many even integers are there between 2 and 100 not including 2 and 100?
48
What is the sum of the even integers from 2 to 100 inclusive?
2550
What is the sum of the 2 integers directly above 100?
203
How many odd integers under 1000 are not divisible by 5?
you can say that 2/10 of every 10 integers is divisible by 5, so multiplying 2/10 by 100, giving you 200/1000 total integers are divisible by 5. half of all integers are odd, so divide 200/1000 by 2 is 100/1000, so you can correctly state that 100 odd integers under 1000 are divisible by 5.
What is the sum of the first 100 positive integers?
To find the sum of the first 100 integers, you first add 1 plus 100 (the first and last numbers of the set) and get 101. Do the same with the next two integers, 2 and 99 and you'll get 101. Since you are adding two integers at a time and there are 100 integers between 1 and 100, you'll get 101, fifty times. Therefore, a shortcut would be to simply multiply 101 times 50 and get 5,050.
How can 50 be a factor of 100?
50 x 2 = 100 They're both integers, they're both factors.
What are the integers between 0 and 100 whose positive square roots are integers?
What are the integers between 0 and 100 whose positive square roots are integers?
Product of 2 consecutive integers that equal 440?
I think you mean consecutive even integers: 20 & 22
How many integers between 100 and 200?
There are 9 integers.
How would you convince a fellow student that the number 0.57 is a rational number?
0.57 can be written as 57/100. 57 and 100 are both integers and therefore 0.57 can be written as a ratio of 2 integers. A number that can be written as a ratio of two integers is a rational number because the word rational comes from ratio.
What is the average of the first ten complete numbers?
if by complete you mean integers then the answer is (1+2+3+4+5+6+7+8+9+10)/10 =55/2 =27.50 if you dont mean integers ,i dont know
WhoFind three consecutive integers whose sum is 300?
The integers are 99, 100 and 101. There is also a set of consecutive even integers whose sum is 300. That set is 98, 100 and 102.
