In a triangle, the sum of the interior angles is always 180 degrees. If angle A is 40 degrees and angle B is 70 degrees, you can find angle C by subtracting the sum of angles A and B from 180 degrees:
C = 180 - (A + B) = 180 - (40 + 70) = 180 - 110 = 70 degrees.
Thus, the measure of angle C is 70 degrees.
it depends on the triangle
To measure a Pythagorean triangle, you identify the lengths of its sides, typically denoted as a, b, and c, where c is the hypotenuse (the longest side). You can confirm it's a Pythagorean triangle by applying the Pythagorean theorem, which states that (a^2 + b^2 = c^2). If this equation holds true, the triangle is a right triangle, and you can measure its sides accordingly. Additionally, you can use tools like a ruler or a measuring tape for physical measurements.
If we are talking about a triangle here, then: A = 61º B = 45º C = 74º But, since you did not specify, there is an infinite number of answers.
The question appears to be a concatenation of two (or more) questions. A triangle, PQR does not have side Bc. It would not have angle b nor a.
Depends from the given information. For example, if it is given the measure of the angle base θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/cos θ If it is given the measure of the angle base θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/sin θ If it is given the measure of the vertex angle θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/sin θ/2 If it is given the measure of the vertex angle θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/cos θ/2 If it is given the length measures of the base b and the height h, the sum of the sides a of the isosceles triangle equals to 2a = √(h4 + b2) (from the Pythagorean theorem)
it depends on the triangle
A = 60 B = 20 C = 140 This can have a large number of answers.
A triangle with side a: 70, side b: 79, and side c: 97 units has an area of 2,730.89 square units.
It depends on what your measuring and the measure of the other given angles. "X" is also known as the missing angle. ex. In triangle ABC, the measure of angle A is 40 and the measure of angle B is 80 find the missing angle. answer- Angle C would be 60 because a triangle's angles add up to 180 degrees.
No.Finding an obtuse triangle that does not have a greater area than any acute triangle will show the statement is false:Consider the obtuse triangle with sides 25, 25, 40 cm; andthe acute triangles with sides 2, 2, 2 cm and 40, 40, 40 cmArea of (A) obtuse triangle = 40 x 12 ÷ 2 = 240 cm2Area of (B) acute 2, 2, 2 cm triangle = 2 x √3 ÷ 2 = √3 cm2 ~= 1.7 cm2Area of (C) acute 40, 40, 40 cm triangle = 40 x (20 x √3) ÷ 2 = 400 x √3 cm2 ~= 692.8 cm2So you can clearly see that area of acute triangle (C) is greater than that of obtuse triangle (B) which is greater than acute triangle (A).Thus the area of obtuse triangle (B) is not greater than that of any acute triangle.(Obtuse triangle A has angles approx 37o, 37o, 106o, whereas triangles B and C are equilateral acute triangles with angles 60o, 60o, 60o.)
The hypotenuse is 56.57 feet.
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how to find the measure of angle C in the following triangle
a*b=(h*B)/2, a&b being the sides of the rectangle, h the height of the triangle and B the base: 8*5=(2B)/2 40=B
need the pic or more info... what is angle B
To measure a Pythagorean triangle, you identify the lengths of its sides, typically denoted as a, b, and c, where c is the hypotenuse (the longest side). You can confirm it's a Pythagorean triangle by applying the Pythagorean theorem, which states that (a^2 + b^2 = c^2). If this equation holds true, the triangle is a right triangle, and you can measure its sides accordingly. Additionally, you can use tools like a ruler or a measuring tape for physical measurements.
Let the numbers be A and B A + B = 70 AB = 70 + 1130 = 1200 : therefore B = 1200/A : Substituting for B gives A + B = A + 1200/A = 70 : A2 + 1200 = 70A : A2 - 70A + 1200 = 0 This equation factorises (A - 30)(A - 40) = 0 When A - 30 = 0 then A = 30 When A - 40 = 0 then A = 40 The special pair of numbers are 30 and 40.