it depends on the triangle
If we are talking about a triangle here, then: A = 61º B = 45º C = 74º But, since you did not specify, there is an infinite number of answers.
The question appears to be a concatenation of two (or more) questions. A triangle, PQR does not have side Bc. It would not have angle b nor a.
Depends from the given information. For example, if it is given the measure of the angle base θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/cos θ If it is given the measure of the angle base θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/sin θ If it is given the measure of the vertex angle θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/sin θ/2 If it is given the measure of the vertex angle θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/cos θ/2 If it is given the length measures of the base b and the height h, the sum of the sides a of the isosceles triangle equals to 2a = √(h4 + b2) (from the Pythagorean theorem)
In a right triangle with the hypotenuse c equals 10 and the angle A equals 50 degrees the angle B equals: 40 degrees.
it depends on the triangle
A = 60 B = 20 C = 140 This can have a large number of answers.
A triangle with side a: 70, side b: 79, and side c: 97 units has an area of 2,730.89 square units.
It depends on what your measuring and the measure of the other given angles. "X" is also known as the missing angle. ex. In triangle ABC, the measure of angle A is 40 and the measure of angle B is 80 find the missing angle. answer- Angle C would be 60 because a triangle's angles add up to 180 degrees.
No.Finding an obtuse triangle that does not have a greater area than any acute triangle will show the statement is false:Consider the obtuse triangle with sides 25, 25, 40 cm; andthe acute triangles with sides 2, 2, 2 cm and 40, 40, 40 cmArea of (A) obtuse triangle = 40 x 12 ÷ 2 = 240 cm2Area of (B) acute 2, 2, 2 cm triangle = 2 x √3 ÷ 2 = √3 cm2 ~= 1.7 cm2Area of (C) acute 40, 40, 40 cm triangle = 40 x (20 x √3) ÷ 2 = 400 x √3 cm2 ~= 692.8 cm2So you can clearly see that area of acute triangle (C) is greater than that of obtuse triangle (B) which is greater than acute triangle (A).Thus the area of obtuse triangle (B) is not greater than that of any acute triangle.(Obtuse triangle A has angles approx 37o, 37o, 106o, whereas triangles B and C are equilateral acute triangles with angles 60o, 60o, 60o.)
The hypotenuse is 56.57 feet.
?
how to find the measure of angle C in the following triangle
a*b=(h*B)/2, a&b being the sides of the rectangle, h the height of the triangle and B the base: 8*5=(2B)/2 40=B
need the pic or more info... what is angle B
Let the numbers be A and B A + B = 70 AB = 70 + 1130 = 1200 : therefore B = 1200/A : Substituting for B gives A + B = A + 1200/A = 70 : A2 + 1200 = 70A : A2 - 70A + 1200 = 0 This equation factorises (A - 30)(A - 40) = 0 When A - 30 = 0 then A = 30 When A - 40 = 0 then A = 40 The special pair of numbers are 30 and 40.
To figure out what the measure of the base angles in an isosceles triangle are, it is important to first understand several things about an isosceles triangle. 1. A triangle has 180 degrees. 2. An isosceles has two equal sides, which means that it also has two equivalent angles. 3. In knowing at least any one angle of an isosceles triangle, it is possible to figure out the other two. Since the base angles are unknown in this question, and they are equivalent to one another, it is a simple algebraic problem. 180 - 70 = 2A 180 is the number of degrees in a triangle 70 is the number of degrees taken up by angle C, with angles A and B being the equivalent base angles. 2a is the double of one base angle. Let's solve. 180 - 70 = 2A 110 = 2A 110/2 = A 55 = A The measure of each base angle is 55.