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if the number is less than 5 round toward the number 1 if the number greater than

a 5 round toward the number 9

Q: What is the method to rounding numbers to the nearest tenth using decimals?

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To the nearest thousand: 1499 To the nearest hundred: 1049 To the nearest ten: 1005 With regards to rounding numbers ending in 5, I advocate rounding so that the previous digit becomes an even digit. If 5s are always rounded up [or down] you introduce an upward [downward] rounding bias. The suggested method avoids introducing a rounding bias and is reproducible by others.

To divide decimals the partial sums method requires that numbers are separated into individual portions. The separated numbers are then solved in long division until eliminated.

If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.

There is a method of rounding, called "floor" rounding, where 14.58 rounds to 14.00, but you're not going to win that argument. Under the most common system of rounding, when rounding to the nearest whole number, you look at the tenths place. If that digit is 5 or higher, you round up. 14.58 rounds to 15

Write both numbers as decimal numbers, then look for terminating decimals between the two.

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To the nearest thousand: 1499 To the nearest hundred: 1049 To the nearest ten: 1005 With regards to rounding numbers ending in 5, I advocate rounding so that the previous digit becomes an even digit. If 5s are always rounded up [or down] you introduce an upward [downward] rounding bias. The suggested method avoids introducing a rounding bias and is reproducible by others.

To divide decimals the partial sums method requires that numbers are separated into individual portions. The separated numbers are then solved in long division until eliminated.

If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.

There is a method of rounding, called "floor" rounding, where 14.58 rounds to 14.00, but you're not going to win that argument. Under the most common system of rounding, when rounding to the nearest whole number, you look at the tenths place. If that digit is 5 or higher, you round up. 14.58 rounds to 15

If you are making use of long division method, the process of dividing a whole number is actually a subset of the process of dividing the decimals. While dividing both you may get a quotient with decimal places. Some exceptions to this do exist in case of whole numbers. Like when you are dividing 100 by 2, the quotient 50 has no decimal places.

Write both numbers as decimal numbers, then look for terminating decimals between the two.

the higher multiple

round or rounding

Computers need a method to store decimals. More to the point, they need a method to manage very large and very small numbers - numbers that we would normally show in scientific notation.

413 cm = 4.13 m Since .13 is less than .50, it rounds DOWN to 4 m by the most common rounding method.

One method is to ignore the sign and treat it like a positive number. Round to the nearest 100 and replace the sign.

If the question is asking, "What is the method for solving 99.9999 equals 100?" then this is based on the process of rounding off a number.Certain questions may ask for the answer to 3 decimal places or 4 significant figures or, as in this example, to the nearest 100.The rule when rounding off numbers is "If the first figure to be discarded is 5 or more then the previous figure is increased by 1".Regard 99.9999 as 099.9999 : As the first figure to be discarded is the 9 shown in bold text and underlined then, as this is greater than 5, the previous figure (0) is increased by 1. So 99.9999 rounded off to the nearest hundred equals 100.