To the nearest thousand: 1499 To the nearest hundred: 1049 To the nearest ten: 1005 With regards to rounding numbers ending in 5, I advocate rounding so that the previous digit becomes an even digit. If 5s are always rounded up [or down] you introduce an upward [downward] rounding bias. The suggested method avoids introducing a rounding bias and is reproducible by others.
To divide decimals the partial sums method requires that numbers are separated into individual portions. The separated numbers are then solved in long division until eliminated.
If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.
There is a method of rounding, called "floor" rounding, where 14.58 rounds to 14.00, but you're not going to win that argument. Under the most common system of rounding, when rounding to the nearest whole number, you look at the tenths place. If that digit is 5 or higher, you round up. 14.58 rounds to 15
Write both numbers as decimal numbers, then look for terminating decimals between the two.
To the nearest thousand: 1499 To the nearest hundred: 1049 To the nearest ten: 1005 With regards to rounding numbers ending in 5, I advocate rounding so that the previous digit becomes an even digit. If 5s are always rounded up [or down] you introduce an upward [downward] rounding bias. The suggested method avoids introducing a rounding bias and is reproducible by others.
To divide decimals the partial sums method requires that numbers are separated into individual portions. The separated numbers are then solved in long division until eliminated.
If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.If you mean 8 1/2, you have to find the nearest integer. It is exactly between 8 and 9. Different rounding methods handle this different; a commonly used rounding method will always round up in this case.
There is a method of rounding, called "floor" rounding, where 14.58 rounds to 14.00, but you're not going to win that argument. Under the most common system of rounding, when rounding to the nearest whole number, you look at the tenths place. If that digit is 5 or higher, you round up. 14.58 rounds to 15
If you are making use of long division method, the process of dividing a whole number is actually a subset of the process of dividing the decimals. While dividing both you may get a quotient with decimal places. Some exceptions to this do exist in case of whole numbers. Like when you are dividing 100 by 2, the quotient 50 has no decimal places.
Write both numbers as decimal numbers, then look for terminating decimals between the two.
the higher multiple
round or rounding
Computers need a method to store decimals. More to the point, they need a method to manage very large and very small numbers - numbers that we would normally show in scientific notation.
413 cm = 4.13 m Since .13 is less than .50, it rounds DOWN to 4 m by the most common rounding method.
One method is to ignore the sign and treat it like a positive number. Round to the nearest 100 and replace the sign.
If the average of a set of numbers has a remainder, it typically means that the sum of the numbers in the set is not evenly divisible by the total count of numbers in the set. This can occur when there are fractions or decimals involved in the calculation of the average. To address this situation, you may need to consider rounding the average to a certain number of decimal places or using a different method of calculating the average that accounts for the remainder.