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How do you find maximum or minimum of a function?
y=2x2-3x2-12x+5=0
Is -12x plus 12x a monomial?
No. It's a binomial, (whose value happens to be zero no matter what 'x' is).
What statement describes the equation y equals 12x?
A function.
How do i write -12x plus 3y 15 so that y is a function of x?
If you mean -12x+3y = 15 then y = 4x+5
What is the LCM of 12x 22 and 4x squared?
That will depend on the value of x
How do you find maximum or minimum of a function?
y=2x2-3x2-12x+5=0
What is the maximum value of the function y equals -6x2-12x-1?
y = -6x2 - 12x - 1We recognize this as the equation of a parabola opening downward, but we don't need to know that in order to answer the question.At the extremes of a function (local max or min), the first derivative of the function = zero.The first derivative of the given function with respect to 'x' is dy/dx = -12x -12Set -12x - 12 = 0.-x - 1 = 0x = -1y = -6x2 - 12x - 1 = -6(1) - 12(-1) - 1 = -6 + 12 - 1 = 5
Determine the maximum or minimum value of y-3x2 12x-7 by completing the square?
Every polynomial defines a function, often called P. Linear and and quadratic function belong to a family of functions known as polynomial functions, which often are called P(x). When P(x) = 0, we call it an equation. Any value of x for which P(x) = 0 is a root of the equation and a zero of the function. Polynomials of the first few degrees have a special names such as:Degree 0: Constant functionDegree 1: Linear functionDegree 2: Quadratic functionDegree 3: Cubic functionDegree 4: Quartic functionDegree 5: Quintic functionSo, if we work a little bit to the given expression, we can turn it in a polynomial function of the second degree.y - 3x^2 = 12x - 7y - 3x^2 + 3x^2 = 12x - 7 + 3x^2y = 3x^2 + 12x - 7Let's write y = f(x) and f(x) = 3x^2 + 12x - 7, where a = 3, b = 12, and c = -7.Since a > 0, the parabola opens upward, so we have a minimum value of the function. The maximum or minimum value of the quadratic function occurs at x = -(b/2a).x = -12/6 = -2To find the minimum value of the function, which is also the y-value, we will find f(-2).f(-2) = 3(-2)^2 + 12(-2) - 7f(-2) = 12 - 24 - 7 = -19Thus the minimum value of the function is -19, and the vertex is (-2, -19)To find zeros, we solve f(x) = 0. So,f(x) = 3x^2 + 12x - 7f(x) = 03x^2 + 12x - 7 = 0 In order to solve this equation by completing the square, we need the constant term on the right hand side;3x^2 + 12x = 7 Add the square of one half of the coefficient of x to both sides, (6^2)3x^2 +12x + 36 = 7 + 36 Use the formula (a + b)^2 = a^2 + 2ab + b^2;(3x + 6)^2 = 43 Take the square root of both sides, and solve for x;3x + 6 = (+ & -)square root of 433x + 6 = (+ & -)(square root of 43) Subtract 6 to both sides;3x = (+ & -)(square root of 43) - 6 Divide both sides by 3;x = (square root of 43)/3 - 2 or x = -(square root of 43)/3 - 2The solution are (square root of 43) - 2 and -(square root of 43) - 2
How do you write 3y-12x equals 0 in function form?
3Y - 12X = 0add 12X to both sides3Y = 12Xdivide both sides integers by 3(3/3)Y = (12/3)XY = 4X---------------the function
What is the equation for the axis of symmetry of the quadratic function f(x) 3x2 12x - 2?
It is x = +/- 2 depending on whether the second term in the equation is -12x or +12x.
Is -12x plus 12x a monomial?
No. It's a binomial, (whose value happens to be zero no matter what 'x' is).
Identify the maximum value of the function y equals -6x2-12x-1?
y = - 6x2 - 12x - 1 A second degree equation graphs as a parabola, and has only one max or min. At that point, the first derivative y' = 0. dy/dx = - 12x - 12 = 0 - x - 1 = 0 ==> x = - 1 At that point, y = - 6( 1 ) - 12( - 1 ) - 1 = - 6 + 12 - 1 = 5. The max value of the function is 5, and occurs when x = -1.
What statement describes the equation y equals 12x?
A function.
What is the value of x in 12x-14 equals 5x?
12x - 14 = 5x12x = 5x + 147x = 14x = 2
How do i write -12x plus 3y 15 so that y is a function of x?
If you mean -12x+3y = 15 then y = 4x+5
3x 2-12x plus 9?
The value of X in the equation 3x 2-12x plus 9 is 1.25.
What is x2 plus 12x equals o?
x2 + 12x = 0 is an equation that describes a parabola. This parabola would have a minimum value and no maximum. That minimum can be found by taking its derivative and solving for zero: y = x2 + 12x dy/dx = x + 12 0 = x + 12 x = -12 Then take that x value and plug it in to the original equation: y = (-12)2 + 12(-12) y = 144 - 144 y = 0 So the focal point of the parabola is at (-12, 0) If you want to factor it, that would come to: x(x + 12) = 0
