To find the image of the point (4, 3) after a -90-degree rotation (which is equivalent to a 90-degree clockwise rotation), you can use the rotation formula: (x', y') = (y, -x). Applying this to the point (4, 3), the new coordinates become (3, -4). Therefore, the image of the point (4, 3) after a -90-degree rotation is (3, -4).
To find the image of the point (4, 3) after a 90-degree rotation counterclockwise about the origin, you can use the transformation formula for rotation. The new coordinates will be (-y, x), which means the image of the point (4, 3) will be (-3, 4).
To find the image of the point (3, 5) after a rotation of -270 degrees (which is equivalent to a 90-degree rotation clockwise), you can use the rotation formula. The new coordinates will be (y, -x), resulting in the point (5, -3). Thus, the image of the point (3, 5) after a -270-degree rotation is (5, -3).
The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.
The answer is A(-7, 2). To solve this problem, first convert the given points into vectors and then apply the given transformations. The vector for point T is (8, -5). After the half turn, the vector becomes (-5, -8). The vector for point W is (-2, -7). After a 90 degree clockwise rotation, the vector becomes (7, -2). The vector for point R is (6, -3). After a 90 degree counter-clockwise rotation, the vector becomes (-3, 6). Finally, the vector for point B is (-2, 7). After a 90 degree counter-clockwise rotation, the vector becomes (-7, 2). Therefore, the answer is A(-7, 2).
To find the image of the point (4, 3) after a -90-degree rotation (which is equivalent to a 90-degree clockwise rotation), you can use the rotation formula: (x', y') = (y, -x). Applying this to the point (4, 3), the new coordinates become (3, -4). Therefore, the image of the point (4, 3) after a -90-degree rotation is (3, -4).
(-4,-3) anything with a 180 degree rotation regardless of being postive or negative is always negative the numbers in parenthesis.
To find the image of the point (4, 3) after a 90-degree rotation counterclockwise about the origin, you can use the transformation formula for rotation. The new coordinates will be (-y, x), which means the image of the point (4, 3) will be (-3, 4).
To find the image of the point (3, 5) after a rotation of -270 degrees (which is equivalent to a 90-degree rotation clockwise), you can use the rotation formula. The new coordinates will be (y, -x), resulting in the point (5, -3). Thus, the image of the point (3, 5) after a -270-degree rotation is (5, -3).
(x,y) to (x,-y). You would keep the x the same, but turn the y negative. This is actually the rule for a 90 degree counterclockwise rotation, but they're the same thing, they would go to the same coordinates.
It is the start of the second rotation, hence it is in the 1st quadrant.
The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.
The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.
The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.
The answer is A(-7, 2). To solve this problem, first convert the given points into vectors and then apply the given transformations. The vector for point T is (8, -5). After the half turn, the vector becomes (-5, -8). The vector for point W is (-2, -7). After a 90 degree clockwise rotation, the vector becomes (7, -2). The vector for point R is (6, -3). After a 90 degree counter-clockwise rotation, the vector becomes (-3, 6). Finally, the vector for point B is (-2, 7). After a 90 degree counter-clockwise rotation, the vector becomes (-7, 2). Therefore, the answer is A(-7, 2).
The image is (-5, 3)
negative 30