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To find the negative 90-degree rotation of the point (3, 5), you can use the rotation formula for a point (x, y) around the origin. The formula for a negative 90-degree rotation is (y, -x). Applying this to (3, 5) gives you (5, -3). Thus, the negative 90-degree rotation of the point (3, 5) is (5, -3).

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What is the image of point 4 3 if the rotation is -90?

To find the image of the point (4, 3) after a -90-degree rotation (which is equivalent to a 90-degree clockwise rotation), you can use the rotation formula: (x', y') = (y, -x). Applying this to the point (4, 3), the new coordinates become (3, -4). Therefore, the image of the point (4, 3) after a -90-degree rotation is (3, -4).


What is image of point 4 3 if rotation is 90?

To find the image of the point (4, 3) after a 90-degree rotation counterclockwise about the origin, you can use the transformation formula for rotation. The new coordinates will be (-y, x), which means the image of the point (4, 3) will be (-3, 4).


What is the image of point 3 5 if rotation is -270?

To find the image of the point (3, 5) after a rotation of -270 degrees (which is equivalent to a 90-degree rotation clockwise), you can use the rotation formula. The new coordinates will be (y, -x), resulting in the point (5, -3). Thus, the image of the point (3, 5) after a -270-degree rotation is (5, -3).


T (8, -5) half turn W(-2, -7) 90 degrees clockwiseR (6,-3) 90 degrees counter-clockwiseB (-2. 7) 90 degrees counter-clockwise?

The answer is A(-7, 2). To solve this problem, first convert the given points into vectors and then apply the given transformations. The vector for point T is (8, -5). After the half turn, the vector becomes (-5, -8). The vector for point W is (-2, -7). After a 90 degree clockwise rotation, the vector becomes (7, -2). The vector for point R is (6, -3). After a 90 degree counter-clockwise rotation, the vector becomes (-3, 6). Finally, the vector for point B is (-2, 7). After a 90 degree counter-clockwise rotation, the vector becomes (-7, 2). Therefore, the answer is A(-7, 2).


What is the image of point 3 5 if the rotation is -90?

The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.

Related Questions

What is the image of point 4 3 if the rotation is -90?

To find the image of the point (4, 3) after a -90-degree rotation (which is equivalent to a 90-degree clockwise rotation), you can use the rotation formula: (x', y') = (y, -x). Applying this to the point (4, 3), the new coordinates become (3, -4). Therefore, the image of the point (4, 3) after a -90-degree rotation is (3, -4).


What is the image of point 4 3 if the rotation is 180?

(-4,-3) anything with a 180 degree rotation regardless of being postive or negative is always negative the numbers in parenthesis.


What is image of point 4 3 if rotation is 90?

To find the image of the point (4, 3) after a 90-degree rotation counterclockwise about the origin, you can use the transformation formula for rotation. The new coordinates will be (-y, x), which means the image of the point (4, 3) will be (-3, 4).


What is the image of point 3 5 if rotation is -270?

To find the image of the point (3, 5) after a rotation of -270 degrees (which is equivalent to a 90-degree rotation clockwise), you can use the rotation formula. The new coordinates will be (y, -x), resulting in the point (5, -3). Thus, the image of the point (3, 5) after a -270-degree rotation is (5, -3).


What is the rule for a 270 degree clockwise rotation?

(x,y) to (x,-y). You would keep the x the same, but turn the y negative. This is actually the rule for a 90 degree counterclockwise rotation, but they're the same thing, they would go to the same coordinates.


In what quadrant is 361 degree?

In a circle ,there are 4 quadrants,each quadrant have 90 degree angle, therefore 4x90=360 degree so 361 degree angle will be in first quadrant.


T (8, -5) half turn W(-2, -7) 90 degrees clockwiseR (6,-3) 90 degrees counter-clockwiseB (-2. 7) 90 degrees counter-clockwise?

The answer is A(-7, 2). To solve this problem, first convert the given points into vectors and then apply the given transformations. The vector for point T is (8, -5). After the half turn, the vector becomes (-5, -8). The vector for point W is (-2, -7). After a 90 degree clockwise rotation, the vector becomes (7, -2). The vector for point R is (6, -3). After a 90 degree counter-clockwise rotation, the vector becomes (-3, 6). Finally, the vector for point B is (-2, 7). After a 90 degree counter-clockwise rotation, the vector becomes (-7, 2). Therefore, the answer is A(-7, 2).


What is the image of point (3 5) if the rotation is 90?

The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.


What is the image of point 3 5 if the rotation is -90?

The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.


What is the image of point (3 5) if the rotation is -90?

The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.


What is the image of point 3 5 if the rotation is 90?

The image is (-5, 3)


What does 90 over negative 3 equal?

negative 30