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What is the image of point 4 3 if the rotation is -90?
To find the image of the point (4, 3) after a -90-degree rotation (which is equivalent to a 90-degree clockwise rotation), you can use the rotation formula: (x', y') = (y, -x). Applying this to the point (4, 3), the new coordinates become (3, -4). Therefore, the image of the point (4, 3) after a -90-degree rotation is (3, -4).
What is the image of point 3 5 if the rotation is -90?
The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.
What is the image of point (4 3) if the rotation is -180?
The answer will depend on where the centre of rotation is. Since that it not specified, the image could by anywhere.
What is the image of point 4 3 if the rotation is -270?
All rotations, other than those of 180 degrees should be further qualified as being clockwise or counter-clockwise. This one is not and I am assuming that the direction of rotation is the same as measurement of polar angles. Also, a rotation is not properly defined unless the centre of rotation is specified. I am assuming that the centre of rotation is the origin. Without these two assumptions any point in the plane can be the image. With the assumptions, for which there is no valid reason, the image is (3, -4).
T (8, -5) half turn W(-2, -7) 90 degrees clockwiseR (6,-3) 90 degrees counter-clockwiseB (-2. 7) 90 degrees counter-clockwise?
The answer is A(-7, 2). To solve this problem, first convert the given points into vectors and then apply the given transformations. The vector for point T is (8, -5). After the half turn, the vector becomes (-5, -8). The vector for point W is (-2, -7). After a 90 degree clockwise rotation, the vector becomes (7, -2). The vector for point R is (6, -3). After a 90 degree counter-clockwise rotation, the vector becomes (-3, 6). Finally, the vector for point B is (-2, 7). After a 90 degree counter-clockwise rotation, the vector becomes (-7, 2). Therefore, the answer is A(-7, 2).
What is the image of point 4 3 if the rotation is -90?
To find the image of the point (4, 3) after a -90-degree rotation (which is equivalent to a 90-degree clockwise rotation), you can use the rotation formula: (x', y') = (y, -x). Applying this to the point (4, 3), the new coordinates become (3, -4). Therefore, the image of the point (4, 3) after a -90-degree rotation is (3, -4).
What is the image of point 3 5 if the rotation is 90?
The image is (-5, 3)
What is the image of point (3 5) if the rotation is 90?
The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.
What is the image of point 3 5 if the rotation is -90?
The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.
What is the image of point (3 5) if the rotation is -90?
The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.
What is the image of point 3 and 5 if the rotation is 180 degrees?
What is the image of point (3, 5) if the rotation is
What is the image of point (4 3) if the rotation is -180º?
It is: (-4, -3)
What is the image of point (3 5) if the rotation is -180º?
It then is: (-3, -5)
What is the image of point 4 3 if the rotation is -180º?
It is: (-4, -3)
What is the image of point (3 5) if the rotation is -90 degrees?
Conventionally positive angles are measured anticlockwise. It depends where the centre of rotation is, so where would you like the image to be? If the centre is at, say, (3, 5) then the image will be at (3, 5) regardless of the angle of rotation. If the centre is at, say, (3, 3) then the image will be at (5, 3) If the centre is at, say, the origin, ie (0, 0) then the image will be at (5, -3).
What is the image of point (4 3) if the rotation is -180?
The answer will depend on where the centre of rotation is. Since that it not specified, the image could by anywhere.
What is the image of point 3 5 if the rotation is -270 degrees?
(-5,3)
