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The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.

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Q: What is the image of point 3 5 if the rotation is -90?
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What is the image of point (4 3) if the rotation is -180?

The answer will depend on where the centre of rotation is. Since that it not specified, the image could by anywhere.


What is the image of point 4 3 if the rotation is -270?

All rotations, other than those of 180 degrees should be further qualified as being clockwise or counter-clockwise. This one is not and I am assuming that the direction of rotation is the same as measurement of polar angles. Also, a rotation is not properly defined unless the centre of rotation is specified. I am assuming that the centre of rotation is the origin. Without these two assumptions any point in the plane can be the image. With the assumptions, for which there is no valid reason, the image is (3, -4).


T (8, -5) half turn W(-2, -7) 90 degrees clockwiseR (6,-3) 90 degrees counter-clockwiseB (-2. 7) 90 degrees counter-clockwise?

The answer is A(-7, 2). To solve this problem, first convert the given points into vectors and then apply the given transformations. The vector for point T is (8, -5). After the half turn, the vector becomes (-5, -8). The vector for point W is (-2, -7). After a 90 degree clockwise rotation, the vector becomes (7, -2). The vector for point R is (6, -3). After a 90 degree counter-clockwise rotation, the vector becomes (-3, 6). Finally, the vector for point B is (-2, 7). After a 90 degree counter-clockwise rotation, the vector becomes (-7, 2). Therefore, the answer is A(-7, 2).


How many degrees is 2 and one third times a quarter of a rotation?

7/3 x 90 = 210 degrees.


What are the three transformations of math?

The 3 transformations of math are: translation, reflection and rotation. These are the well known ones. There is a fourth, dilation, in which the pre image is the same shape as the image, but the same size in the world