The quartic:
t(n) = -n4 + 12n3 - 44.5n2 - 24.5n + 356 fits the data for n = 1, 2, 3, ...
Putting n = 6 gives t(6) = -97
NB: A more popular version of this question has 129 as the third number.
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∙ 13y agoAt each step the number being subtracted is reduced by 9 298 - 89 = 209 209 - 80 = 129 129 - 71 = 58 58 - 62 = -4 -4 - 53 = -57..........which is the next number.
-57. You are taking away 9 less each time.
-57
-57 (each number that is subtracted from the first is 9 different from the previous (i.e. 298-89=209-80=129-71=58-62=-4-53=-57). As you can see, the amounts that are substracted are 89, 80, 71, 62, 53 (all 9 different from the one before it.)
-66 The sequence can be generated by the following quartic: t(n) = (-3n4 + 42n3 - 177n2 - 358n + 2808)/8 for n = 1, 2, 3, ...
At each step the number being subtracted is reduced by 9 298 - 89 = 209 209 - 80 = 129 129 - 71 = 58 58 - 62 = -4 -4 - 53 = -57..........which is the next number.
The difference between one number and the next in the sequence is decreasing by 9 each time. Therefore, the difference between -4 and the next number will be equal to 62 - 9 = 53. The next number is therefore equal to -4 - 53 = -57.
The sequence is formed by subtracting 89 at the first step and then reducing this figure by 9 at each successive step. 298 - 89 = 209 209 - 80 = 129 129 - 71 = 58 58 - 62 = -4 -4 - 53 = -57........this is the next number in the series.
It is a quadratic sequence (order 2) t(n) = (9n2 - 205n + 792)/2 for n = 1, 2, 3, ... and the next number is -57
298 less 209 is 89 209 less 129 is 80 129 less 58 is 71 58 less -4 is 62 The result of each subsequent equation is 9 less than the previous one (89, 80, 71...). The next result is going to be 62-9=53. The first number in each equation above is the same as the second number in the previous equation: 298 less 209 is 89 209 less 129 is 80So, the next equation will be: -4 less X is 53 Therefore, X is the next number in the original sequence, which resolves to: -57
The next number is 1112.
There are 84 protons and approximately 125 neutrons in a nucleus of 209Po (Polonium), based on its atomic number (84) and its approximate atomic mass of 209.
The natural number N with four factors can be expressed as N = p^3, where p is a prime number. Given that the sum of factors excluding N is 31, the factors are 1, p, p^2, and the sum of these factors is 1 + p + p^2 = 31. Solving the equation p^2 + p - 30 = 0, we find two possible values for p: p = 5 or p = -6. However, since p must be a prime number, the only valid value is p = 5. Therefore, N can have only one value, which is 5^3 = 125.
-57
-57. You are taking away 9 less each time.
-57
-57