125 (the sequence is successive numbers cubed)
The next one is 125.
The sequence represents the cube of integers starting at 1 and increasing by 1 at each step. 13 = 1 : 23 = 8 : 33 = 27 : 43 = 64 : then next two numbers are 53 = 125 : 63 = 216
47 AND 34
Your sequence seems to be a cubed sequence, but you are missing 64 between 27 and 125.13 = 123 = 833 = 2743 = 6453 = 12563 = 216So, next would be 73, which equals 343.
125 (the sequence is successive numbers cubed)
The next one is 125.
The sequence represents the cube of integers starting at 1 and increasing by 1 at each step. 13 = 1 : 23 = 8 : 33 = 27 : 43 = 64 : then next two numbers are 53 = 125 : 63 = 216
1 8 27 64 125 216 343
64. It's the sequence f(n) = n^3
47 AND 34
343.
Your sequence seems to be a cubed sequence, but you are missing 64 between 27 and 125.13 = 123 = 833 = 2743 = 6453 = 12563 = 216So, next would be 73, which equals 343.
25 36 49 64 81 100 121 144
It appears as if the pattern is doubling, therefore the next three numbers are 16, 32, and 64.
The first thing to notice is that all the numbers in the sequence are square numbers. 25=5x5 36=6x6 49=7x7 64=8x8 81=9x9 So the next three numbers to be squared are 10, 11 and 12. 10x10=100 11x11=121 12x12=144 Thus, the next three numbers in the sequence are 100, 121, 144 The equation for the sequence is (n+4)2
125 13 23 43 53...