The nth root of a number is that number which when raised to the nth power (ie when multiplied by itself n times) results in the number. When n=2, it is the square root of the number; when n=3 it is the cube root of the number. To find the nth root of a number, an electronic calculator can be used, using the nth root button [x√y] (though more recent calculators replace the x and y by boxes) viz: <n> [x√y] [2] [4] [4] [=] or with the more recent calculators: [#√#] <n> [Navigate →] [2] [4] [4] [=] where <n> is the nth root, eg for 2nd root (square roots) enter [2]; and the # is being used to represent a box on the keys of the more recent calculator. Considering the rules for indices, the nth root is the the number to the power of 1/n, ie 244^(1/n), thus the calculation can be done using the power button: [2] [4] [4] [^] [(] [1] [÷] <n> [)] [=] With the more recent calculators, the power button is pressed first, the 244 entered, the navigate-right key pressed (to get in to the power part of the input) and then the n entered.
One is always one of the roots. There are n-l other complex roots, evenly spaced around the unit circle in the complex plane.
1/n
Assuming that you mean the nth. root: two - a negative and a positive root.
The answer depends on what information is provided.If you have initial value (Y0), final value (Yn) and number of years (n) then the annual percentage rate is 100*[(yn/y0)^(1/n) - 1] where raising to the power 1/n is finding the nth root.
What does this question mean? -60 has a real cube root, a real fifth root. In fact a real nth root for all odd n.
The nth root of a number is that number which when raised to the nth power (ie when multiplied by itself n times) results in the number. When n=2, it is the square root of the number; when n=3 it is the cube root of the number. To find the nth root of a number, an electronic calculator can be used, using the nth root button [x√y] (though more recent calculators replace the x and y by boxes) viz: <n> [x√y] [2] [4] [4] [=] or with the more recent calculators: [#√#] <n> [Navigate →] [2] [4] [4] [=] where <n> is the nth root, eg for 2nd root (square roots) enter [2]; and the # is being used to represent a box on the keys of the more recent calculator. Considering the rules for indices, the nth root is the the number to the power of 1/n, ie 244^(1/n), thus the calculation can be done using the power button: [2] [4] [4] [^] [(] [1] [÷] <n> [)] [=] With the more recent calculators, the power button is pressed first, the 244 entered, the navigate-right key pressed (to get in to the power part of the input) and then the n entered.
One is always one of the roots. There are n-l other complex roots, evenly spaced around the unit circle in the complex plane.
The answer depends on the value of n.
You can't prove this proposition because it isn't true.Proof: the fifth root of 1024 is 4, and 4 is not irrational.It is true that, when N is an integer greater than 1, the Nth root of any integer greater than 1 is either an integer orirrational, but that's a different matter.
1/n
Root of a number x is the new number y, which can be calculated as y = ( x ) 1/n where n is the root number i.e. nth root of x is y.
Assuming that you mean the nth. root: two - a negative and a positive root.
The nth root of x2 can be expressed as: x2/n Thinking of it that way, we can see that no, it can't always exist - but almost always. The only condition in which it can't exist is when n = 0, as that would give us division by zero.
The answer depends on what information is provided.If you have initial value (Y0), final value (Yn) and number of years (n) then the annual percentage rate is 100*[(yn/y0)^(1/n) - 1] where raising to the power 1/n is finding the nth root.
the nth arrangement is any arrangement that exists. N is a variable just like X.
rearrange the following: A^(1/n)= the nth root of A. eg A to the power 1/2 equals the square root of A. A to the power 1/3 equals the cube root of A. etc.