The nth root of x2 can be expressed as:
x2/n
Thinking of it that way, we can see that no, it can't always exist - but almost always. The only condition in which it can't exist is when n = 0, as that would give us division by zero.
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if you mean X²+8X-5=0: X1=-8/2 - Square root of ((8/2)²+5) X1=-4 - Square root of 21 X1 is about -8.58 X2=-8/2 + Square root of ((8/2)²+5) X2=-4 + Square root of 21 X2 is about 0.58
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
2
1
0