They are: nth term = 6n-4 and the 14th term is 80
3n-2
20-9x=n
By varying the parameters of a quartic polynomial, the nth term can be made whatever you like. But, taking the simplest solution, Un = 2 - 4n for
Un = 29 - 9n
They are: nth term = 6n-4 and the 14th term is 80
It is: nth term = -4n+14
The nth term is: 3n+2 and so the next number will be 20
f(n) = 14 - 6n -6n+20
The nth term is 2 + 3n.
The nth term is 3n+2 and so the next number will be 17
t(n) = 10 - 6n where n = 1, 2, 3, ...
42
It is: 26-8n
The differences are 3, 5, 7, 9,11, ... and the first term is -1; the nth term is: n² - 2
9n+2
It is: 3n+2