It is: 26-6n
They are: nth term = 6n-4 and the 14th term is 80
3n-2
20-9x=n
By varying the parameters of a quartic polynomial, the nth term can be made whatever you like. But, taking the simplest solution, Un = 2 - 4n for
To find the nth term of the sequence -4, -1, 4, 11, 20, 31, we first identify the pattern in the differences between the terms: 3, 5, 7, 9, 11, which increases by 2 each time. This suggests a quadratic relationship. The nth term can be expressed as ( a_n = n^2 + n - 4 ). Thus, the nth term of the sequence is ( a_n = n^2 + n - 4 ).
They are: nth term = 6n-4 and the 14th term is 80
It is: nth term = -4n+14
The nth term is: 3n+2 and so the next number will be 20
f(n) = 14 - 6n -6n+20
The nth term is 2 + 3n.
The nth term is 3n+2 and so the next number will be 17
42
t(n) = 10 - 6n where n = 1, 2, 3, ...
3n-2
It is: 3n+2
20-9x=n
By varying the parameters of a quartic polynomial, the nth term can be made whatever you like. But, taking the simplest solution, Un = 2 - 4n for