They are: nth term = 6n-4 and the 14th term is 80
3n-2
20-9x=n
By varying the parameters of a quartic polynomial, the nth term can be made whatever you like. But, taking the simplest solution, Un = 2 - 4n for
Un = 29 - 9n
They are: nth term = 6n-4 and the 14th term is 80
It is: nth term = -4n+14
The nth term is: 3n+2 and so the next number will be 20
f(n) = 14 - 6n -6n+20
The nth term is 2 + 3n.
The nth term is 3n+2 and so the next number will be 17
t(n) = 10 - 6n where n = 1, 2, 3, ...
42
Well, isn't that just a lovely pattern we have here? Each term is increasing by 4, isn't that delightful? So, if we want to find the nth term, we can use the formula: nth term = first term + (n-1) * common difference. Just like painting a happy little tree, we can plug in the values and find the nth term with ease.
Well, darling, the pattern here is increasing by odd numbers starting from 1. So, the nth term for this sequence would be n^2 - 2, where n represents the position of the term in the sequence. But hey, if math isn't your thing, just keep enjoying the ride with those quirky numbers!
9n+2
It is: 3n+2