By varying the parameters of a quartic polynomial, the nth term can be made whatever you like.
But, taking the simplest solution,
Un = 2 - 4n for
They are: nth term = 6n-4 and the 14th term is 80
The sequence given is -2, -8, -18, -32, -50. To find the nth term, we first observe the differences between consecutive terms: -6, -10, -14, -18, which show that the second differences are constant at -4. This indicates that the nth term can be expressed as a quadratic function. By fitting the sequence to the form ( a_n = An^2 + Bn + C ), we find that the nth term is ( a_n = -2n^2 + 2n - 2 ).
To find the nth term of the sequence 5, 15, 29, 47, 69, we first determine the differences between consecutive terms: 10, 14, 18, and 22. The second differences are constant at 4, indicating that the nth term is a quadratic function. By fitting the quadratic formula ( an^2 + bn + c ) to the sequence, we find that the nth term is ( 2n^2 + 3n ). Thus, the nth term of the sequence is ( 2n^2 + 3n ).
It is: 26-6n
3n-2
It is: nth term = -4n+14
f(n) = 14 - 6n -6n+20
The nth term would be -2n+14 nth terms: 1 2 3 4 Sequence:12 10 8 6 This sequence has a difference of -2 Therefore it would become -2n. Replace n with 1 and you would get -2. To get to the first term you have to add 14. Therefore the sequence becomes -2n+14. To check your answer replace n with 2, 3 or 4. You will still obtain the number in the sequence that corresponds to the nth term. :)
The nth term is (2n - 12).
The nth term is 2 + 3n.
The nth term is 3n+2 and so the next number will be 17
They are: nth term = 6n-4 and the 14th term is 80
The given sequence appears to be increasing by 10 each time. To find the nth term, we can use the formula for arithmetic sequences: nth term = first term + (n-1) * common difference. In this case, the first term is 4 and the common difference is 10. Therefore, the nth term for this sequence would be 4 + (n-1) * 10, which simplifies to 10n - 6.
42
The given sequence is decreasing by 2 each time, starting from 12. To find the nth term, we can use the formula for an arithmetic sequence: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, (a_1 = 12), (d = -2), and we need to find the general formula for the nth term. Therefore, the nth term for the sequence 12 10 8 6 4 is (a_n = 12 + (n-1)(-2)), which simplifies to (a_n = 14 - 2n).
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
Tn = 10 + n2