3n-2
a (sub n) = 11 + (n - 1) x d
The sequence 5, 8, 11, 14, 17 is an arithmetic progression where each term increases by 3. The first term (a) is 5, and the common difference (d) is 3. The nth term can be expressed using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 5 + (n-1) \cdot 3 = 3n + 2 ).
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
It is: nth term = 5-4n and so the next term will be -19
This is an arithmetic sequence which starts at 14, a = 14, and with a common difference of -1, d = -1. We can use the nth term formula an = a + (n - 1)d to get an = 14 + (n - 1)(-1) = 14 - n + 1 = 15 - n.
a (sub n) = 11 + (n - 1) x d
3n - 1
20 - (3 * (n - 1))
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
The nth term of the sequence is 2n + 1.
If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
It is: nth term = 5-4n and so the next term will be -19
42
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
The nth term is 4n-1 and so the next term will be 19
The nth term of the sequence is (n + 1)2 + 2.