-8n+33 , lol is this ur maths homework or summin?
It is: nth term = 35-9n
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
It is increasing by 4 and the nth term is 4n+1
[ 25 - 6n ] is.
tn = n2
2n^2-1
It is: nth term = 35-9n
9, 17, 25, 33, 41
The nth term is: 5-6n
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
The nth term is 6n+1 and so the next term will be 31
7n+4
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
3n - 1
It is increasing by 4 and the nth term is 4n+1
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
n2