To find the nth term of the sequence 2, 16, 54, 123, 250, we can examine the differences between consecutive terms: 14, 38, 69, and 127. The second differences yield a consistent pattern, suggesting a cubic polynomial. By deriving the general form and solving for coefficients, the nth term can be expressed as ( n^3 + n^2 + n ). Thus, the nth term is ( n^3 + n^2 + n ).
The nth term is equal to 4n.
The Nth term in the series is [ 2N ] .
Clearly, if you omit the sign, the nth. term will be 4n. The alternating sign can easily be expressed as a power of (-1), so in summary, the nth. term is (-1)n4n.
If you mean: 2 4 8 16 32 64 it is 2^nth term and so the next number is 128
To determine the nth term of the sequence 25, 16, 7, we first identify the pattern. The sequence appears to be decreasing by 9, then by 9 again, suggesting a consistent difference. This leads to a formula for the nth term: ( a_n = 34 - 9n ), where ( a_1 = 25 ) for n=1. Thus, the nth term can be expressed as ( a_n = 34 - 9n ).
The nth term is equal to 4n.
The Nth term in the series is [ 2N ] .
The nth term is 9n-2
The nth term is 3n+7 and so the next number will be 22
The nth term is: 3n+1 and so the next number will be 16
The nth term is 22n and so the next number will be 5*22 = 110
Clearly, if you omit the sign, the nth. term will be 4n. The alternating sign can easily be expressed as a power of (-1), so in summary, the nth. term is (-1)n4n.
16
If you mean: 2 4 8 16 32 64 it is 2^nth term and so the next number is 128
fu
The nth term is n2.
2n