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What is the fifth term of the arithmetic sequence 7 4 1?
As you are taking 3 away each time, the 5th term will be -5.
What is the nth term of the sequence 2 4 6 8?
Ok, take the formula dn+(a-d) this is just when having a sequence with a common difference dn+(a-d) when d=common difference, a=the 1st term, n=the nth term - you have the sequence 2, 4, 6, 8... and you want to find the nth term therefore: dn+(a-d) 2n+(2-2) 2n Let's assume you want to find the 5th term (in this case, the following number in the sequence) 2(5) = 10 (so the fifth term is 10)
How far does the stone fall during the 5th second Find and use the explicit formula. What is the first term of the sequence How far does the stone fall during the 5th second Find and use the explicit?
56
What is the nth term for 15 23 31 39 47?
Well, darling, the nth term for this sequence is 8n + 7. You just add 8 to each term to get the next one, simple as that. So, if you want the 100th term, just plug in n=100 and you'll get 807. Easy peasy lemon squeezy!
What is the nth term is 6n - 1?
5
What is the 5th term of the sequence which has a first term of 17?
That depends what the pattern of the sequence is.
What is the 5th term of this geometric sequence 100 20 4 0.8 ...?
0.16
What is the fifth term of the arithmetic sequence 7 4 1?
As you are taking 3 away each time, the 5th term will be -5.
What is the 5th term of the given sequence 31-1-3.....?
If you mean: +3 +1 -1 -3 then it is -5
How is the recursive form of a sequence sometimes more useful than the closed form where a rule is found to find any term based on its position in the sequence?
"The recursive form is very useful when there aren't too many terms in the sequence. For instance, it would be fairly easy to find the 5th term of a sequence recursively, but the closed form might be better for the 100th term. On the other hand, finding the closed form can be very difficult, depending on the sequence. With computers or graphing calculators, the 100th term can be found quickly recursively."
How to find the 5th term in an arithmetic sequence using the explicit rule?
Nth number in an arithmetic series equals 'a + nd', where 'a' is the first number, 'n' signifies the Nth number and d is the amount by which each term in the series is incremented. For the 5th term it would be a + 5d
What is the nth term of the sequence 2 4 6 8?
Ok, take the formula dn+(a-d) this is just when having a sequence with a common difference dn+(a-d) when d=common difference, a=the 1st term, n=the nth term - you have the sequence 2, 4, 6, 8... and you want to find the nth term therefore: dn+(a-d) 2n+(2-2) 2n Let's assume you want to find the 5th term (in this case, the following number in the sequence) 2(5) = 10 (so the fifth term is 10)
How far does the stone fall during the 5th second Find and use the explicit formula. What is the first term of the sequence How far does the stone fall during the 5th second Find and use the explicit?
56
What does the payment term net 5th of 3rd month mean?
The payment term "net 5th of 3rd month" means that payment is due on the 5th day of the third month following the invoice date. For example, if the invoice is dated in January, the payment would be due on March 5th. This term gives the buyer additional time to settle the invoice compared to standard net payment terms, which typically require payment within a month.
What is the 21st term in this sequence 1 -2 -5 -8 -11?
This is arithmetic progression with common difference of minus three...Formula:First Term +[ (number of term you want-1)*(common difference which is negative 3)]ExampleFor the 3RD term: -5=1+[(3-1)*(-3)]=1+[-6]= -5For 5TH term: -11=1+[(5-1)*(-3)]=1+(-12)=-11.: For the 21st term:=1+[(21-1)*(-3)]=1+[-60]= -59:D
How was the Fibonacci pattern formed?
1 1 2 3 5 etc start with 1 and 1 and to get the 3rd term 1+1 = 2 add 2nd and 3rd term to get 4th --- 1 + 2 = 3 add 3rd and 4th term to get the 5th --- 2 + 3 = 5 etc
What is the next series 14101931?
If the sequence is 1,4,10,19,31,...... Then the sequence formula is, 1 + 3/2n(n - 1) Confirm 5th term....1 + (3/2 x 5 x 4) = 1 + 30 = 31 the 6th (next) term = 1 + (3/2 x 6 x 5) = 1 + 45 = 46
