The sequence 2, 5, 8, 11 is an arithmetic sequence where the first term is 2 and the common difference is 3. The nth term can be expressed using the formula: ( a_n = 2 + (n - 1) \cdot 3 ). Simplifying this gives ( a_n = 3n - 1 ). Thus, the nth term is ( 3n - 1 ).
The 'n'th term is [ 4 - 3n ].
The sequence 5, 7, 9, 11 is an arithmetic sequence where each term increases by 2. The first term (n=1) is 5, and the common difference is 2. The nth term can be expressed as ( a_n = 5 + (n - 1) \times 2 ), which simplifies to ( a_n = 2n + 3 ).
3n(n+1] + 5 is the nth term
It is: nth term = 5-4n and so the next term will be -19
The sequence 5, 8, 11, 14, 17 is an arithmetic progression where each term increases by 3. The first term (a) is 5, and the common difference (d) is 3. The nth term can be expressed using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 5 + (n-1) \cdot 3 = 3n + 2 ).
The nth term is 2 + 3n.
The nth term is 3n+2 and so the next number will be 17
The nth term is: 3n-7 and so the next number will be 11
The nth term is: 3n-7 and so the next number will be 11
It is: 3n+2
2n+5
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
The nth term is: 3n+2 and so the next number will be 20
The sequence 5, 7, 9, 11 is an arithmetic sequence where each term increases by 2. The first term (n=1) is 5, and the common difference is 2. The nth term can be expressed as ( a_n = 5 + (n - 1) \times 2 ), which simplifies to ( a_n = 2n + 3 ).
3n(n+1] + 5 is the nth term