The 'n'th term is [ 4 - 3n ].
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
The given sequence is -1, -6, -11, -16, -21. To find the nth term, we can identify that the sequence decreases by 5 each time. Thus, the nth term can be expressed as: ( a_n = -1 - 5(n-1) ), which simplifies to ( a_n = -5n + 4 ).
The given sequence is 1, 6, 13, 22, 33. To find the nth term, we can observe that the differences between consecutive terms are 5, 7, 9, and 11, which indicates that the sequence is quadratic. The nth term can be expressed as ( a_n = n^2 + n ), where ( a_n ) is the nth term of the sequence. Thus, the formula for the nth term is ( a_n = n^2 + n ).
The sequence 3, 7, 11 is an arithmetic sequence where the first term is 3 and the common difference is 4. The nth term formula for an arithmetic sequence can be expressed as ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. Substituting the values, the nth term formula for this sequence is ( a_n = 3 + (n - 1) \cdot 4 ), which simplifies to ( a_n = 4n - 1 ).
The nth term of the sequence is 2n + 1.
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
The nth term is 4n-1 and so the next term will be 19
The nth term of the sequence is (n + 1)2 + 2.
10n + 1
The given sequence is -1, -6, -11, -16, -21. To find the nth term, we can identify that the sequence decreases by 5 each time. Thus, the nth term can be expressed as: ( a_n = -1 - 5(n-1) ), which simplifies to ( a_n = -5n + 4 ).
The given sequence is 1, 6, 13, 22, 33. To find the nth term, we can observe that the differences between consecutive terms are 5, 7, 9, and 11, which indicates that the sequence is quadratic. The nth term can be expressed as ( a_n = n^2 + n ), where ( a_n ) is the nth term of the sequence. Thus, the formula for the nth term is ( a_n = n^2 + n ).
I believe the answer is: 11 + 6(n-1) Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence. The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
It works out as -5 for each consecutive term