a (sub n) = 11 + (n - 1) x d
5, 8, 11, 14 and 17.
It is: nth term = 35-9n
Term-to-term is -3
t(n) = 6*n - 1 where n = 1, 2, 3, ...
It is: 3n+2
3n - 1
The nth term is 3n+2 and so the next number will be 17
The nth term is: 3n+2 and so the next number will be 20
a (sub n) = 11 + (n - 1) x d
20 - (3 * (n - 1))
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
5, 8, 11, 14 and 17.
It is: 2n+9
The nth term is: 2n+7 and so the next number will be 19
2n+5
This appears to be a declining arithmetic series. If it is, the next term is 5, because each term is 3 less than the preceding term.=================================The 'N'th term is: [ 23 - 3N ].