a (sub n) = 11 + (n - 1) x d
The sequence 5, 8, 11, 14, 17 is an arithmetic progression where each term increases by 3. The first term (a) is 5, and the common difference (d) is 3. The nth term can be expressed using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 5 + (n-1) \cdot 3 = 3n + 2 ).
5, 8, 11, 14 and 17.
It is: nth term = 35-9n
Term-to-term is -3
t(n) = 6*n - 1 where n = 1, 2, 3, ...
It is: 3n+2
3n - 1
The nth term is 3n+2 and so the next number will be 17
The nth term is: 3n+2 and so the next number will be 20
20 - (3 * (n - 1))
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
The sequence 5, 8, 11, 14, 17 is an arithmetic progression where each term increases by 3. The first term (a) is 5, and the common difference (d) is 3. The nth term can be expressed using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 5 + (n-1) \cdot 3 = 3n + 2 ).
5, 8, 11, 14 and 17.
It is: 2n+9
The nth term is: 2n+7 and so the next number will be 19
2n+5
It is 6n+5 and so the next term will be 35