560
They are: nth term = 6n-4 and the 14th term is 80
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
20-9x=n
It is: 26-6n
The nth term is: 5n
560
Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.
The given sequence is an arithmetic sequence with a common difference of 6, as each term increases by 6. To find the nth term of an arithmetic sequence, we use the formula: nth term = a + (n-1)d, where a is the first term, d is the common difference, and n is the term number. In this case, the first term a = 2, the common difference d = 6, and the term number n is not specified. Therefore, the nth term of the sequence 2, 8, 14, 20, 26 is 2 + (n-1)6.
t(n) = n2 + n + 8
The nth term of the sequence is expressed by the formula 8n - 4.
They are: nth term = 6n-4 and the 14th term is 80
f(n) = 14 - 6n -6n+20
Divide the sequence by 5 and the answer becomes very obvious: 1, 4, 9, 16,...N2 So, 5, 20, 45, 80,...5N2
This is an arithmetic progression. In general, If an A.P. has a first term 'a', and a common difference 'd' then the nth term is a + (n - 1)d. In the sequence shown in the question, the first term is 0 and the common difference is 5, therefore the nth term is, 0 + (n - 1)5. This can be rearranged to read : 5(n - 1) For example : the 7th term is 30 : 5(7 - 1) = 5 x 6 = 30.
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
5n-5, because its the 5 time table (called 5n) minus 5 each time