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To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
Double it minus the previous number.
[ 25 - 6n ] is.
T(n) = 25 - 6n
When n = 1, sequence term (call it y) = 7. Each unit increase in n results in an increase of 6 in y, so when n = 5, y = 31. Sequence is therefore 7, 13, 19, 25, 31 etc.