Double it minus the previous number.
The sequence 12, 13, 14, 15 is an arithmetic sequence where each term increases by 1. The nth term can be expressed as ( a_n = 12 + (n - 1) \times 1 ), which simplifies to ( a_n = 11 + n ). Therefore, the nth term of the sequence is ( a_n = n + 11 ).
The sequence 7, 9, 11, 13, 15 is an arithmetic sequence where the first term (a) is 7 and the common difference (d) is 2. The nth term can be calculated using the formula: ( a_n = a + (n-1) \cdot d ). Thus, the nth term is given by ( a_n = 7 + (n-1) \cdot 2 ), which simplifies to ( a_n = 2n + 5 ).
To find the nth term of this sequence, we first need to determine the pattern or rule governing the sequence. By examining the differences between consecutive terms, we can see that the sequence is increasing by 9, 15, 21, 27, and so on. This indicates that the nth term is given by the formula n^2 + 1.
To find the nth term of the sequence 5, 15, 29, 47, 69, we first determine the differences between consecutive terms: 10, 14, 18, and 22. The second differences are constant at 4, indicating that the nth term is a quadratic function. By fitting the quadratic formula ( an^2 + bn + c ) to the sequence, we find that the nth term is ( 2n^2 + 3n ). Thus, the nth term of the sequence is ( 2n^2 + 3n ).
To find the nth term of the sequence 0, 3, 8, 15, 24, 35, we can observe the pattern in the differences between consecutive terms. The differences are 3, 5, 7, 9, 11, which form an arithmetic sequence with a common difference of 2. This suggests that the nth term can be represented by the formula ( n^2 - n ), where n starts from 1. Thus, the nth term for the given sequence is ( n^2 - n ).
The nth term in this sequence is 4n + 3.
The nth term is 4n-1 and so the next term will be 19
The sequence 12, 13, 14, 15 is an arithmetic sequence where each term increases by 1. The nth term can be expressed as ( a_n = 12 + (n - 1) \times 1 ), which simplifies to ( a_n = 11 + n ). Therefore, the nth term of the sequence is ( a_n = n + 11 ).
It is: nth term = 29-7n
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
The nth term is 2n+5 and so the next number is 17
The sequence 7, 9, 11, 13, 15 is an arithmetic sequence where the first term (a) is 7 and the common difference (d) is 2. The nth term can be calculated using the formula: ( a_n = a + (n-1) \cdot d ). Thus, the nth term is given by ( a_n = 7 + (n-1) \cdot 2 ), which simplifies to ( a_n = 2n + 5 ).
To find the nth term of this sequence, we first need to determine the pattern or rule governing the sequence. By examining the differences between consecutive terms, we can see that the sequence is increasing by 9, 15, 21, 27, and so on. This indicates that the nth term is given by the formula n^2 + 1.
To find the nth term of the sequence 5, 15, 29, 47, 69, we first determine the differences between consecutive terms: 10, 14, 18, and 22. The second differences are constant at 4, indicating that the nth term is a quadratic function. By fitting the quadratic formula ( an^2 + bn + c ) to the sequence, we find that the nth term is ( 2n^2 + 3n ). Thus, the nth term of the sequence is ( 2n^2 + 3n ).
To find the nth term of the sequence 0, 3, 8, 15, 24, 35, we can observe the pattern in the differences between consecutive terms. The differences are 3, 5, 7, 9, 11, which form an arithmetic sequence with a common difference of 2. This suggests that the nth term can be represented by the formula ( n^2 - n ), where n starts from 1. Thus, the nth term for the given sequence is ( n^2 - n ).
1 +3 =4 +3+4 =11 +3+4+4 =22 +3+4+4+4 37 +3+4+4+4+4 .... u can c where i am goin here
If you mean: 15 11 7 3 then the nth term is 19-4n