0.0027 moles.
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To determine the number of moles in 0.000264 g of Li2HPO4, you first need to calculate the molar mass of Li2HPO4. The molar mass of Li2HPO4 is 115.79 g/mol. Next, you can use the formula n = m/M, where n is the number of moles, m is the mass in grams, and M is the molar mass. Plugging in the values, you get n = 0.000264 g / 115.79 g/mol ≈ 2.28 x 10^-6 moles of Li2HPO4.
To find the number of molecules in 9.0 g of steam (water vapor), first determine the number of moles. The molar mass of water (H₂O) is approximately 18.02 g/mol. Therefore, 9.0 g of steam is equivalent to ( \frac{9.0 \text{ g}}{18.02 \text{ g/mol}} \approx 0.5 ) moles. Since one mole contains Avogadro's number of molecules ((6.022 \times 10^{23}) molecules/mol), the total number of molecules is (0.5 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} \approx 3.01 \times 10^{23} ) molecules.
You look up the atomic weight for calcium, which is equivalent to the number of grams per mole. Then you divide the 0.85 g by this number, to get the number of moles. From there, it should be easy to convert to millimoles.
3.03
It depends on the substance and its molar mass.In order to convert from grams to formula units, you must first convert grams to moles, then moles to formula units (grams --> moles --> formula units).1. Divide the mass (g) of the given substance by the substance's molar mass.2. Multiply the number of moles found in Step 1 (above) by Avogadro's number (6.022 x 1023).---- Mass substance ----- X 6.022 x 1023 formula unitsMolar mass substanceCONVERSION FACTOR47.63g substance x 1 mol substance ---- x ----- Avogadro's number///////////////////// molar mass (g) substance ////// 1 mol substance