0.0027 moles.
To determine the number of moles in 0.000264 g of Li2HPO4, you first need to calculate the molar mass of Li2HPO4. The molar mass of Li2HPO4 is 115.79 g/mol. Next, you can use the formula n = m/M, where n is the number of moles, m is the mass in grams, and M is the molar mass. Plugging in the values, you get n = 0.000264 g / 115.79 g/mol ≈ 2.28 x 10^-6 moles of Li2HPO4.
To find the number of molecules in 9.0 g of steam (water vapor), first determine the number of moles. The molar mass of water (H₂O) is approximately 18.02 g/mol. Therefore, 9.0 g of steam is equivalent to ( \frac{9.0 \text{ g}}{18.02 \text{ g/mol}} \approx 0.5 ) moles. Since one mole contains Avogadro's number of molecules ((6.022 \times 10^{23}) molecules/mol), the total number of molecules is (0.5 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} \approx 3.01 \times 10^{23} ) molecules.
To determine the number of molecules in 15.9 g of IF7 (iodine heptafluoride), first calculate the molar mass of IF7. The molar mass is approximately 144.9 g/mol. Next, use the formula: number of moles = mass (g) / molar mass (g/mol). Thus, ( \text{number of moles} = \frac{15.9 , \text{g}}{144.9 , \text{g/mol}} \approx 0.1096 , \text{mol} ). Finally, multiply the number of moles by Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol) to find the number of molecules: (0.1096 , \text{mol} \times 6.022 \times 10^{23} \approx 6.60 \times 10^{22}) molecules of IF7.
To find the concentration of HgCl2 in a solution, you first need to calculate the number of moles of HgCl2. The molar mass of HgCl2 (mercury(II) chloride) is approximately 271.5 g/mol. Therefore, 10.9 grams of HgCl2 is about 0.0402 moles (10.9 g / 271.5 g/mol). To find the concentration in moles per liter (M), divide the number of moles by the volume in liters: 0.0402 moles / 2 liters = 0.0201 M. Thus, the concentration of HgCl2 in the solution is 0.0201 M.
The quotient of 15 and g is expressed as ( \frac{15}{g} ). This represents the result of dividing 15 by the variable g. If g is a non-zero number, this quotient can be calculated numerically. If g equals zero, the quotient is undefined.
To determine the number of moles of aluminum present, we need to first determine the molar mass of aluminum, which is approximately 26.98 g/mol. We can then use the formula: moles = mass / molar mass. Plugging in the values, we get moles = 15 g / 26.98 g/mol ≈ 0.56 moles of aluminum.
The mass of 15 moles of tungsten is 2.757,6 g.
the equation is Xg multiplied by the moles/grams of X = moles of X (the grams cancel leaving you with moles) 607g Ar x 1 mole/ 39.95g = 15.19 moles
To find the number of moles of Na in 15 g of NaCl, you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Since Na makes up 39.34% of the molar mass of NaCl, you can calculate the moles of Na as (15 g / 58.44 g/mol) * 0.3934 = 0.255 moles of Na.
15 moles of 02 equal 480 g.
The number of moles is mass in g/molar mass in g.
The formula is: number of moles = g Be/9,012.
To calculate the total number of atoms in 15 g of CaH2, we first need to find the number of moles of CaH2 using its molar mass. The molar mass of CaH2 is 42.08 g/mol. Therefore, 15 g of CaH2 is equal to 15/42.08 = 0.356 moles of CaH2. Since each mole of CaH2 contains 3 atoms (1 calcium atom and 2 hydrogen atoms), there are 0.356 * 3 = 1.068 moles of atoms in 15 g of CaH2. This is equivalent to 1.068 * 6.022 x 10^23 = 6.44 x 10^23 atoms.
The number of moles 9,92.10e-5.
To find the molarity (M) of the solution, first calculate the number of moles of NaCl. The molar mass of NaCl is approximately 58.44 g/mol. Therefore, 15 g of NaCl is about 0.256 moles (15 g ÷ 58.44 g/mol). Molarity is calculated as moles of solute per liter of solution, so for 600 mL (0.6 L), the concentration is approximately 0.427 M (0.256 moles ÷ 0.6 L).
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
22.99 g of C28H44O is equal to 0,058 moles.