9
Let the ones digit be represented as ( x ). Since the ten digit is 9 more than the ones digit, it can be expressed as ( x + 9 ). However, since digits can only range from 0 to 9, the only solution is when the ones digit ( x ) is 0, making the ten digit 9. Therefore, the two-digit number is 90.
For the number 25, the 5 is the ones digit (and the 2 is the tens digit). So, for 99 the second 9 from left to right is the ones digit.
To express 9 ones and 3 tenths in decimal form, you would write it as 9.3. This is because each digit's place value increases by a factor of 10 as you move from right to left - the digit 3 is in the tenths place, so it represents 3 tenths. The digit 9 is in the ones place, so it represents 9 ones.
The 9 in 879 represents nine ones or nine units
No, a number with a 9 in the ones place is not always divisible by 3. For a number to be divisible by 3, the sum of its digits must be divisible by 3, regardless of the digit in the ones place. For example, the number 29 has a 9 in the ones place, but its digit sum (2 + 9 = 11) is not divisible by 3.
9
Let the ones digit be represented as ( x ). Since the ten digit is 9 more than the ones digit, it can be expressed as ( x + 9 ). However, since digits can only range from 0 to 9, the only solution is when the ones digit ( x ) is 0, making the ten digit 9. Therefore, the two-digit number is 90.
The answer depends on what the tens digit is greater than, and what the ones digit does then.
It is a 3. Look at the ones digit of successive powers of 7; this need only be done by considering the multiplication of the ones digit of the previous power of 7 by 7 (as this is the only calculation that affects the ones digit as each successive power of 7 is the previous power multiplied by 7) and taking the result modulus 10 (to extract the new ones digit as any excess over 9 is carried into the tens column): 7¹ → 7 mod 10 = 7 7² → (7×7) mod 10 = 9 7³ → (9×7) mod 10 = 3 7⁴ → (3×7) mod 10 = 1 7⁵ → (1×7) mod 10 = 7 At this point the pattern of the ones digit will obviously repeat the sequence of the four digits {7, 9, 3, 1}. To find the ones digit of any power of 7, take that power modulus 4 use that digit from the four digit sequence. Note that when taking the number modulus 4, the result will be in the range 0-3; when the result is 0, use the 4th digit from the sequence. 2015 mod 4 = 3 → the third digit of {7, 9, 3, 1}, which is 3, will be the ones digit of 7²⁰¹⁵.
For the number 25, the 5 is the ones digit (and the 2 is the tens digit). So, for 99 the second 9 from left to right is the ones digit.
The possible values for the ones digit of a number are the integers from 0 to 9. This means the ones digit can be any of the following: 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9. Each digit represents the last digit in a number's decimal representation.
91 since the ones digit is 8 less than 9 and the two digits, 9+1 = 10, a two-digit number.
To express 9 ones and 3 tenths in decimal form, you would write it as 9.3. This is because each digit's place value increases by a factor of 10 as you move from right to left - the digit 3 is in the tenths place, so it represents 3 tenths. The digit 9 is in the ones place, so it represents 9 ones.
9
The 9 in 879 represents nine ones or nine units
If the first digit is 9, you have 9 options (0-8) for the second digit. If the first digit is 8, you have 8 options (0-7) for the second digit. Etc. This leaves you with the arithmetic series: 0 + 1 + 2 + 3 + ... + 9.
The ones digit in even numbers can be any of the following: 0, 2, 4, 6, or 8. This is because even numbers are divisible by 2, meaning they can be expressed as 2 multiplied by another integer. The ones digit is the digit in the ones place of a number, which can range from 0 to 9.