The operation appears to involve subtracting 1 from the quotient of each input number divided by 5. Specifically, for each input number ( x ), the output can be calculated as ( \text{output} = \frac{x}{5} + 3 ). For example, for the input 5, the output is ( \frac{5}{5} + 3 = 4 ). This pattern holds for all given input numbers.
The output is 1 more than 10 times the input.
The answer depends on what the "number machine" does. For example, if it quadruples, the input should be 10; if it halves, the input should 80; if it adds 10, the input should be 30; and so on.
10
There are infinitely many possible rules. One simple rule, for input n isU(n) = (n^2 + 3n + 2)/2 = (n + 1)*(n + 2)/2or, equivalently, the sum of all the integers from 1 to n+1.
The mechanical advantage is 10.We use machines to make our work easier and faster.Mechanical advantage gives an idea of how much a mechanism makes our work easier.It is the factor by which the mechanism multiplies the force or torque applied.One way of calculating mechanical advantage is:Mechanical Advantage= (output force)/ (input force)So using this formula to answer the question above, the result is20/2 = 10
A table in which you put in a number and out comes another number. Usually more than one groups of numbers. And almost ALWAYS follows a rule such as: Input x3=Output or Input -23= Output Input | Output 2 | 4 10 | 20 16 | 32 In this table you can see that the rule is Input x2 = Output Hope This helped!
50
If you know that the number input will always be three digits: output = 10 * (int)(input / 100) + (input % 10); If you want to idiot proof it (eg. too many digits): output = 10 * (int)((input % 1000) / 100) + (input % 10);
10
Assuming by in you mean input and out you mean output. Input is the value that goes in while the output is the value you receive. Between these terms is a rule, called the nth term that will always work to help you find the input/output. For example. Our input is 2, and our output is 10 the rule here could be the input multiplied by 5 equals the output, or it can be something extremely difficult and unfathomable even to a banker...
Sure thing, sweetheart. First, you'll need a start symbol followed by a process symbol to input the numbers. Connect that to a decision symbol asking if 10 numbers have been entered yet. If not, loop back to the input process. Once all 10 numbers are in, use a process symbol to calculate the average and finally end with an output symbol displaying the average. Easy peasy lemon squeezy!
The output is 1 more than 10 times the input.
A 10 KVA 3-phase UPS will have an input and output current that depends on the specific voltage of the system. You can calculate the current by dividing the apparent power (in this case 10 KVA) by the square root of 3 multiplied by the voltage. For example, for a 208V system, the input and output current would be approximately 28.8 amps.
The answer is the quantity of the two numbers
The answer depends on what the "number machine" does. For example, if it quadruples, the input should be 10; if it halves, the input should 80; if it adds 10, the input should be 30; and so on.
here, the power required by the receiver is the output power and that required from the source is input power. Gain in dB=10 log(output power/input power) we have, loss in dB = -gain in dB = 10 log(input power/output power) or, 50 = 10 log(input power/10nW) or, anti-log(5) = input power/10 nW so the power required from the source is antilog(5)*10nW = 1 mW
IC 7402 is different from the other type of IC like 7404,7408,7432 and 7400 when it is connected to have an output desired... if you noticed all i mentioned ic is connected from left to the right. input pin 1 and 2, output pin 3 input pin 4 and 5, output pin 6 input pin 13 and 12, output pin 11 input pin 10 and 9, output pin 8 while in nor gate, to have the desired output it must be connected from right to left... input pin 2 and 3, output pin 1 input pin 5 and 6, output pin 4 input pin 8 and 9, output pin 10 input pin 11 and 12, output pin 13