The operation appears to involve subtracting 1 from the quotient of each input number divided by 5. Specifically, for each input number ( x ), the output can be calculated as ( \text{output} = \frac{x}{5} + 3 ). For example, for the input 5, the output is ( \frac{5}{5} + 3 = 4 ). This pattern holds for all given input numbers.
The output is 1 more than 10 times the input.
The answer depends on what the "number machine" does. For example, if it quadruples, the input should be 10; if it halves, the input should 80; if it adds 10, the input should be 30; and so on.
10
To determine the rule connecting the inputs (1234 and 5) to the outputs (26 and 12), we can look for a pattern. One possible interpretation is that the first output (26) could represent the sum of the digits of 1234 (1 + 2 + 3 + 4 = 10) multiplied by 2. The second output (12) might represent the input number 5 multiplied by 2. Thus, the rule could involve summing the digits of the first input and applying a multiplication factor, while directly multiplying the second input.
A calculation involving input values like addition, subtraction, multiplication, and division is a mathematical operation that combines numbers to produce a result. For example, if you have the numbers 10 and 5, you can add them to get 15, subtract to get 5, multiply to get 50, or divide to get 2. These operations form the basis of arithmetic and are fundamental in various applications, from simple math problems to complex calculations in science and finance.
A table in which you put in a number and out comes another number. Usually more than one groups of numbers. And almost ALWAYS follows a rule such as: Input x3=Output or Input -23= Output Input | Output 2 | 4 10 | 20 16 | 32 In this table you can see that the rule is Input x2 = Output Hope This helped!
50
If you know that the number input will always be three digits: output = 10 * (int)(input / 100) + (input % 10); If you want to idiot proof it (eg. too many digits): output = 10 * (int)((input % 1000) / 100) + (input % 10);
The output when the input is 5 depends on the specific function or context in which the input is being used. For example, if the function is to double the input, the output would be 10. If it’s a mathematical function like squaring, the output would be 25. Please provide more details for a precise answer.
10
Assuming by in you mean input and out you mean output. Input is the value that goes in while the output is the value you receive. Between these terms is a rule, called the nth term that will always work to help you find the input/output. For example. Our input is 2, and our output is 10 the rule here could be the input multiplied by 5 equals the output, or it can be something extremely difficult and unfathomable even to a banker...
Sure thing, sweetheart. First, you'll need a start symbol followed by a process symbol to input the numbers. Connect that to a decision symbol asking if 10 numbers have been entered yet. If not, loop back to the input process. Once all 10 numbers are in, use a process symbol to calculate the average and finally end with an output symbol displaying the average. Easy peasy lemon squeezy!
A 10 KVA 3-phase UPS will have an input and output current that depends on the specific voltage of the system. You can calculate the current by dividing the apparent power (in this case 10 KVA) by the square root of 3 multiplied by the voltage. For example, for a 208V system, the input and output current would be approximately 28.8 amps.
The output is 1 more than 10 times the input.
The answer is the quantity of the two numbers
The answer depends on what the "number machine" does. For example, if it quadruples, the input should be 10; if it halves, the input should 80; if it adds 10, the input should be 30; and so on.
here, the power required by the receiver is the output power and that required from the source is input power. Gain in dB=10 log(output power/input power) we have, loss in dB = -gain in dB = 10 log(input power/output power) or, 50 = 10 log(input power/10nW) or, anti-log(5) = input power/10 nW so the power required from the source is antilog(5)*10nW = 1 mW