{-4,-5}
6x-y=-14 2x-3y=6
yes plug it in 3y-2x=14 3(2)-2(-4)=14 6+8=14 14=14
x = 3 and y = 4 so the lines intersect at (3, 4)
2x + 5y = 16 -2x - 3y = -14 2y = 2 y = 1 / x = 5.5 (5.5,1) or (5 1/2,1)
(10, 2)
The ordered pair is (-1, -2).
{-4,-5}
(-4,-5)
2x plus 3y
10
x = 12 y = 2 (12,2) satifies the equation
There are infinitely many ordered pairs. The coordinates of each of the infinite number of points on the straight line defined by 2x + 6y = 24 (or equivalently, 3y = -x + 12) is an ordered pair that satisfies the requirements.
6x-y=-14 2x-3y=6
2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)
There are an infinite number of solutions to this equation, some of which are (9,0), (12,2), (15,4), (18,6), (21,8)
yes plug it in 3y-2x=14 3(2)-2(-4)=14 6+8=14 14=14