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What is 5 over 7 minus 5 over 21?
5/7 - 5/21 = 15/21 - 5/21 = 10/215/7 - 5/21 = 15/21 - 5/21 = 10/215/7 - 5/21 = 15/21 - 5/21 = 10/215/7 - 5/21 = 15/21 - 5/21 = 10/21
What are 7 consectutive odd numbers of seven?
9, 11, 13, 15, 17, 19, 21
What is the simplest form of 45 and 21?
45/21 = 15/7
What are the values of x y and z when the equal terms of 7x plus 11y plus 13z have a sum of 15 and a product of 125 showing work?
If: 7x+11y+13z = 15 Then: 7(15/21)+11(15/33)+13(15/39) = 15 because 5+5+5 =15 So it follows: 7(15/21)*11(15/33)*13(15/39) = 125 because 5*5*5 = 125 Therefore: x = 15/21 y = 15/33 and z = 15/39 Or as: x = 5/7 y = 5/11 and z = 5/13
What fraction is equivalent to 7 whole and 13 over21?
7 and 13/21 is equivalent to the fraction 154/21.
What is 13 plus 21 - 7 plus 12?
13 + 21 - 7 + 12 = 15
What is 4 over 6 divided by 7 over 13?
(4/6) / (7/13) = 2/3 * (13/7) = 26/21 or 15/21
What is 5 over 7 minus 5 over 21?
5/7 - 5/21 = 15/21 - 5/21 = 10/215/7 - 5/21 = 15/21 - 5/21 = 10/215/7 - 5/21 = 15/21 - 5/21 = 10/215/7 - 5/21 = 15/21 - 5/21 = 10/21
What is 13 sevenths of 21?
13/7 of 21 is 39.
What are 7 consectutive odd numbers of seven?
9, 11, 13, 15, 17, 19, 21
What are the next two numbers in the pattern 1 3 7 13 19?
21 and 13. The pattern is t(n) = (-n4 + 10n3 - 23n2 + 38n - 12)/12
What is the simplest form of 45 and 21?
45/21 = 15/7
What are the values of x y and z when the equal terms of 7x plus 11y plus 13z have a sum of 15 and a product of 125 showing work?
If: 7x+11y+13z = 15 Then: 7(15/21)+11(15/33)+13(15/39) = 15 because 5+5+5 =15 So it follows: 7(15/21)*11(15/33)*13(15/39) = 125 because 5*5*5 = 125 Therefore: x = 15/21 y = 15/33 and z = 15/39 Or as: x = 5/7 y = 5/11 and z = 5/13
Which fraction is bigger 7 8 or 13 15?
The actual answer is 7/8.
Which ratios is equivalent to 15 over 21 with lower terms?
15/21 in lower terms is 5/7.It is 5/7.
What fraction is equivalent to 7 whole and 13 over21?
7 and 13/21 is equivalent to the fraction 154/21.
What is a number that is not divisible by 2?
7 11 17 13 15 21 23 27 and so forth
