Assuming the figures you give are length and width of a rectangle,
perimeter = 2(L + W)= 2 x(13.5 +12.2) = 2 x 25.7 = 51 .4
area = L x W = 13.5 x 12.2 =164.7
First find the length of this very very small house and let the length be x: Perimeter = 2(x+25) = 122 inches 2x+50 = 122 2x = 122-50 2x = 72 x = 36 So the length = 36 inches Area = 36*25 = 900 square inches
Area = 3*45 = 135 square feet. Perimeter = 2*(3 + 45) = 2*48 = 96 feet.
To find the dimensions of a parking lot with an area of 918 square meters and a perimeter of 122 meters, we can set the length as ( l ) and the width as ( w ). The equations are ( lw = 918 ) and ( 2(l + w) = 122 ). Solving these equations simultaneously, we find that the dimensions are approximately 39 meters in length and 23.5 meters in width.
Perimeter = 4*Side so that Side = Perimeter/4 Area of a rhombus = Side * Altitude so Altitude = Area/Side = Area/(Perimeter/4) = 4*Area/Perimeter
Even if you knew how many sides the polygon has, you stillcould not calculate its perimeter with that much information.Examples:-- An equilateral triangle with area of 20 has perimeter of 20.3885 .-- A square with area of 20 has perimeter of 17.889(rounded).-- A rectangle with area of 20 can have any perimeter more than 17.889 .4 by 5 . . . . area = 20, perimeter = 182 by 10 . . . area = 20, perimeter = 241 by 20 . . . area = 20, perimeter = 42..etc.
Let the length be x:- Perimeter = 2(x+25) = 122 inches 2x+50 = 122 2x = 122-50 2x = 72 x = 36 Check: 36+36+25+25 = 122 inches Area = 36*25 = 900 square inches
135*90 = 12150 square units of area, 135+90= 225 the perimeter 112.5+112.5= new rectangle perimeter = 225 units 112.5*112.5 = 12656.25 square units of area.
First find the length of this very very small house and let the length be x: Perimeter = 2(x+25) = 122 inches 2x+50 = 122 2x = 122-50 2x = 72 x = 36 So the length = 36 inches Area = 36*25 = 900 square inches
Area = 3*45 = 135 square feet. Perimeter = 2*(3 + 45) = 2*48 = 96 feet.
The maximum area is attained when the rectangle is, in fact, a square. Since the perimeter = 48 feet, the maximum length for a square = 48/4 = 12 feet. So max area = 122 = 144 square feet.
To find the dimensions of a parking lot with an area of 918 square meters and a perimeter of 122 meters, we can set the length as ( l ) and the width as ( w ). The equations are ( lw = 918 ) and ( 2(l + w) = 122 ). Solving these equations simultaneously, we find that the dimensions are approximately 39 meters in length and 23.5 meters in width.
It is area, not perimeter!
Perimeter = 4*Side so that Side = Perimeter/4 Area of a rhombus = Side * Altitude so Altitude = Area/Side = Area/(Perimeter/4) = 4*Area/Perimeter
area 63 and perimeter is 32
It can be 56.25 or anything less, but not more. You can't tell the area from the perimeter, and you can't tell the perimeter from the area. -- if each side is 7.5, the perimeter is 30, and the area is 56.25 -- if it's (5 by 10), the perimeter is still 30, and the area is 50 -- if it's (4 by 11), the perimeter is still 30, and the area is 44 -- if it's (3 by 12), the perimeter is still 30, and the area is 36 -- if it's (2 by 13), the perimeter is still 30, and the area is 26 -- if it's (1 by 14), the perimeter is still 30, and the area is 14
In which jobs we use perimeter and area?
Area : 44cm² Perimeter : 30cm