To find the perimeter of a rectangle, you add up the lengths of all its sides. In this case, the rectangle has two sides of 14 cm and two sides of 32 cm. Therefore, the perimeter would be 14 + 14 + 32 + 32 = 92 cm. To find the area of a rectangle, you multiply the length by the width. In this case, the length is 32 cm and the width is 14 cm. Therefore, the area would be 32 x 14 = 448 square cm.
32
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
They will be both the same because the perimeter of the square is 32 units and the perimeter of the rectangle is also 32 units
Area = 27*32 = 864 square cm Perimeter = 27+27+32+32 = 118 cm
32
how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
47
Perimeter = 32 inches. Area = 55 square inches.
They will be both the same because the perimeter of the square is 32 units and the perimeter of the rectangle is also 32 units
Area = 27*32 = 864 square cm Perimeter = 27+27+32+32 = 118 cm
The area of a rectangle with a perimeter of 32 units and a width of 6 units the area is 80 square units.Improved Answer:-Area = 6*10 = 60 square unitsPerimeter = 6+6+10+10 = 32 units
For example, a 1x15 rectangle and a 2x14 rectangle. They both have perimeter of 32, but they have areas of 15 and 28, respectively.
It is not possible to answer the question because you have not defined what 32 measures: is it the area of the rectangle, its perimeter, its diagonal or some other property?
If the perimeter is 32 sq cm, there is a very serious problem since the perimeter is a linear measure, not an area! Leaving that aside, the length of the rectangle is 10 cm and the breadth is 6 cm.
If you restrict yourself to integers, the answer is 24 feet.