Area = 144 sq inches => Length of side, L = 12 inches => Perimeter = 4*L = 48 inches.
Area = 12 sq inches so each side is sqrt(12) inches So perimeter = 4*side = 4*sqrt(12) = 13.86 inches (to 2 dp).
If the area is 100 squinches then each side must be 10 inches and it has 4 sides...
The area is 96*sqrt(3) = 166.3 sq inches, approx.
b and h both equal 30 (square); area = 30 X 30 = 900 SQ IN
Area = 144 sq inches => Length of side, L = 12 inches => Perimeter = 4*L = 48 inches.
48 sq. in. (12+12+12+12)
38 inches = perimeter 2*(w+l); 88 sq inches = Area (w*l)
21.2 sq inches.
* It is unclear if the question is asking about two rectangles, each with a perimeter of 16, or two rectangles whose perimeters sum to 16. This answer assumes the former.Other than the 4x4 square, which coincidentally has both a perimeter and area of 16, some examples would be:1 x 7 rectangle : perimeter 16 in. , area 7 sq. in2 x 6 rectangle : perimeter 16 in., area 12 sq. in3 x 5 rectangle: perimeter 16 in., area 15 sq. inYou can calculate that for a given perimeter, the largest area is found in the square with a side measurement of P/4, i.e. the length and the width are the same.
(6.06 x 3.5) = 21.20 sq in.
Because a perimeter is measured in linear units while an area is measured in square units.
Area = 9 sq inches Length of side = sqrt(9) = 3 inches Perimeter = 4*Length of side = 4*3 = 12 inches
Area = 12 sq inches so each side is sqrt(12) inches So perimeter = 4*side = 4*sqrt(12) = 13.86 inches (to 2 dp).
If the area is 100 squinches then each side must be 10 inches and it has 4 sides...
5
1 side = 50 / 4 = 12.5 inches, so area = 12.5 * 12.5 = 156.25 sq. inches