Suppose the shorter side is 2x cm.
Then the longer side is 3x cm
By Pythagoras, (2x)2 + (3x)2 = 262
ie 4x2 + 9x2 = 262
so that 13x2 = 262
x2 =52
so that x = 2*sqrt(13)
Then perimeter = 10x = 20*sqrt(13)
The perimeter of rectangle A would then be 80 because 80 to 100 is 4 to 5 simplified and the area of triangle A would depend on the sides and area of rectangle B which have not been given.
To find the perimeter of a rectangle we need to know the length of its sides. P = 2L + 2W Let L = 8, and W = √(102 - 82) = √(100 - 64) = √36 = 6 (by the Pythagorean theorem, where the hypotenuse is the diagonal and legs are the sides of the rectangle). Thus, P = 2(8) + 2(6) = 16 + 12 = 28.
The perimeter of a rectangle is the sum of the four sides.
The length of the diagonal of a rectangle with adjacent sides measuring 820cm and 1200cm is about 1453.4cm
By Pythagoras, the other side is 24 inches long. So the perimeter is 2*(10+24) = 2*34 = 68 inches.
By the length of its sides, by its perimeter, by the ratio of its adjacent sides.
A diagonal cannot be a side of a rectangle, and a side cannot be a diagonal.
The perimeter of rectangle A would then be 80 because 80 to 100 is 4 to 5 simplified and the area of triangle A would depend on the sides and area of rectangle B which have not been given.
To find the perimeter of a rectangle we need to know the length of its sides. P = 2L + 2W Let L = 8, and W = √(102 - 82) = √(100 - 64) = √36 = 6 (by the Pythagorean theorem, where the hypotenuse is the diagonal and legs are the sides of the rectangle). Thus, P = 2(8) + 2(6) = 16 + 12 = 28.
The perimeter of a rectangle is the sum of the four sides.
Square the diagonal and take away the square of width, this gives you the square of the other side. Add the square root of the two sides and multiply by two.
The perimeter of the rectangle is the sum of its 4 sides.
no No. You need to know the length of a rectangle's sides in order to calculate the perimeter.
The length of one diagonal is not sufficient to determine its sides and so its perimeter.
The perimeter of a rectangle is the sum of its 4 sides.
If the length to width ratio is 4 to 5 then the length to width ratio is 4 to 5no matter what the perimeter. If the perimeter is 70 feet then the sides are 15.555... and 19.444... feet respectively.
The length of the diagonal of a rectangle with adjacent sides measuring 820cm and 1200cm is about 1453.4cm