It is: 2*(36+23) = 118 cm
Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter
The perimeter of a rectangle is 2 x length + 2 x width. If the width is 16 then 78 = 2 x length + 2 x 16 2 x length = 78 - 32 = 46 length = 23. For the perimeter to be greater than 78 cm, the length must be greater than 23 cm
Perimeter = 2(Length + Width)38 = 2*(7.5 + W)38 = 15 + 2W so 2W = 23 so that W = 11.5 cmA peculiar result since normally the length is larger than the width.
The perimeter of a 9.5 x 11.5 inch rectangle is 42 inches. To find the perimeter of a rectangle we use the formula Length * 2 + Width * 2 That gives us the following expression. 9.5 * 2 + 11.5 * 2 19 + 23 42
OK so we have two formulas: Length = width + 5 (since legth is 5 more than width) length + width + length + width = perimeter= 82 (form. for perm.) so we can replace every instance of "length" with "width + 5" since they are the same. width + 5 + width + width + 5 + width = 82 4xwidth + 10 = 82 4X width = 72 width = 23 so now go back and replace "width" with 23. length = 23 + 5 length = 28 There you go.
Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter
if the perimeter is 46m, then side + length = 23 so we need two values, when added together are 23, with a difference of 11 6 + 17 = 23, (and have a difference of 11) therefore the length = 17m, width = 6m
Let X represent the length, then X-4 represents the width. Perimeter of the rectangle is length plus width multiplied by two. Hence, 2(X + X - 4) = 100; 4X - 8 = 100; 4X = 108; X = 27. The length is 27 mm and the width is 27 - 4 = 23 mm. width = w length = w + 4 perimeter = w + w + w + 4 + w + 4 = 100 4w + 8 = 100 4w = 92 w = 23 width = 23 length = 27 area = 23 x 27 = 621
Divide the known perimeter by 2... giving 23. 23 - 5 = 18. 18 /2 = 9. 9 + 5 = 14 ! To confirm the answer... 14 + 14 + 9 + 9 = 46.
The perimeter of a rectangle is 2 x length + 2 x width. If the width is 16 then 78 = 2 x length + 2 x 16 2 x length = 78 - 32 = 46 length = 23. For the perimeter to be greater than 78 cm, the length must be greater than 23 cm
Perimeter = 2(Length + Width)38 = 2*(7.5 + W)38 = 15 + 2W so 2W = 23 so that W = 11.5 cmA peculiar result since normally the length is larger than the width.
The area of a rectangle with a width of 9 and length of 23 is 207 square units.
The area of rectangle is : 7820.0
To work out the area of a rectangle, multiply the length and the width. Therefore: Area=23*20=460
The perimeter of a 9.5 x 11.5 inch rectangle is 42 inches. To find the perimeter of a rectangle we use the formula Length * 2 + Width * 2 That gives us the following expression. 9.5 * 2 + 11.5 * 2 19 + 23 42
118
Length + width = half of perimeter = 37 in. 37 - 9 = 28, half of 28 = 14 which is the width, and the length is 23