The distance from (0,0) to (8,6) is 10
The distance from (8,6) to (-3,4) is approximately 11.18
The distance from (-3,4) to (0,0) is 5
... so the perimeter is approximately 26.18
With sides of 5 and 12, you can make a triangle with any perimeter you want between 24 and 34. If you call them "legs" because they are the sides of a right triangle, then the hypotenuse is 13, and the perimeter is 30.
A triangle with sides 34/3 in length. A square with sides 34/4 in length. Any regular polygon with sides 34/n in length, with n being the number of sides. A circle with radius 34/(2pi) There are infinite possibilities. Take a piece of string 34 units long. Any shape you can make out of this will have a perimeter of 34, provided that the two ends touch.
Perimeter = sum of three sides = 96 cm One side of 34cm, another of 25 cm so the third is 96 - 34 -25 = 37 cm
length = 34 and width = 3 Perimeter = 34+34+3+3 = 74 Area = 34*3 = 102
√34 (square root of 34) or 5.83
With sides of 5 and 12, you can make a triangle with any perimeter you want between 24 and 34. If you call them "legs" because they are the sides of a right triangle, then the hypotenuse is 13, and the perimeter is 30.
A triangle with sides 34/3 in length. A square with sides 34/4 in length. Any regular polygon with sides 34/n in length, with n being the number of sides. A circle with radius 34/(2pi) There are infinite possibilities. Take a piece of string 34 units long. Any shape you can make out of this will have a perimeter of 34, provided that the two ends touch.
Perimeter = sum of three sides = 96 cm One side of 34cm, another of 25 cm so the third is 96 - 34 -25 = 37 cm
6:00 pm
length = 34 and width = 3 Perimeter = 34+34+3+3 = 74 Area = 34*3 = 102
The maximum area for a rectangle of fixed perimeter is that of the square that can be formed with the given perimeter. 136/4 = 34, so that the side of such a square will be 34 and its area 342 = 1156.
34 00 S, 64 00 W
40° 00′ 34″ North, 75° 08′ 00″ West
To find the area of a rectangle, you multiply the width by the length. In this case, the area would be 34 ft x 10 ft = 340 square feet. The perimeter of a rectangle is found by adding up all the sides, which in this case would be 2(34 ft) + 2(10 ft) = 68 ft + 20 ft = 88 feet.
If the given dimensions are that of a rectangle then perimeter is: 34 feet
34 cm
√34 (square root of 34) or 5.83