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length = 34 and width = 3

Perimeter = 34+34+3+3 = 74

Area = 34*3 = 102

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Q: What are the dimensions of a rectangle that has a perimeter of 74 and an area of 102?
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What is the dimensions of a rectangle that has a perimeter of 74 units and an area of 102 square units?

Width = 3 Length = 34


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50' in Length by 1' in Width...50 x 1 = 50 :: 50+50+1+1=102


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The perimeter of a square is 40 meters - what is its area?

(40/4)2 = 102 = 100m2.


What is the length and width of the perimeter 102?

You can't tell the length and width from the perimeter. There are an infinite number of of possibilities. The only thing you can tell for sure is that the length and width add up to 51 (assuming you are asking about a rectangle, other shapes could have much different lengths and widths). A circle with a perimeter of 102 has a length and a width of approximately, 32.268.


What is the area of a square that has a perimeter of 40 meters?

Answer 100 ---- If the perimeter of a square is 40 meters, then each side has lenght 10 meters. This is because the formula for perimeter is 4L where L is the lenght. Now, the area is L2 which is 102 =100


What is the width of a rectangle if 14 the length and the perimeter is 130?

If the width of the rectangle is 14, then there are two sides of 14. Subtracting this from 130 gives 130 - (14 x 2) = 102. The two remaining sides, added together, must equal 102. Therefore, each side would equal 102/2 = 51. Don't forget to include the appropriate units in your answer.


What is perimeter of a rectangle with a side of 8 and diagonal of 10?

To find the perimeter of a rectangle we need to know the length of its sides. P = 2L + 2W Let L = 8, and W = √(102 - 82) = √(100 - 64) = √36 = 6 (by the Pythagorean theorem, where the hypotenuse is the diagonal and legs are the sides of the rectangle). Thus, P = 2(8) + 2(6) = 16 + 12 = 28.