Q: What is the perimeter of an octagon that has an area of 43560 sq ft?

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The area of a lot is not enough information to determine its perimeter. The most compact perimeter is approx 740 feet, which is attained by a circular lot. Consider the following rectangular plots, each is of area 1 acre: 100 ft * 435.6ft : perimeter = 1071.2 ft 10 ft * 4356 ft : perimeter = 8732 ft 1 ft * 4356 ft : perimeter = 87122 ft 0.1 ft * 43560 ft : perimeter = 871200.2 ft ... 0.000001 ft * 43,560,000,000 ft : perimeter = 87,120,000,000 ft (approx) = 16,500,000 miles. There is virtually no limit to how much the first dimension can be reduced and the perimeter increased.

The area is not sufficient information to determine the perimeter. First of all, there is no reason to suppose that the area is rectangular as opposed to circular or triangular or some other simple or complicated shape. So, all that can be said is that the perimeter is greater than 178.97 feet, a perimeter that is attained when the area is a circle. If the area is a rectangle, it could be 25.49 ft * 100 ft so that the perimeter is approx 250.98 ft or 2.549 ft * 1000 ft and a perimeter of 2005.10 ft or 0.2549 ft * 10000 ft and a perimeter of 2000.51 ft or 0.0002549 ft * 10000000 ft and a perimeter of 2000000 ft. By making the rectangle thinner and longer, the perimeter can be increased without limit.

The smallest possible perimeter is 20-ft, but there is no largest possible perimeter.You can make it as large as you want, with no limit.Examples:5-ft x 5-ft . . . . area = 25 ft2 . . . perimeter = 20 ft2.5-ft x 10-ft . . area = 25 ft2 . . . perimeter = 25 ft1-ft x 25-ft . . . area = 25 ft2 . . . Perimeter = 52 ft6-in x 50-ft . . . area = 25 ft2 . . . Perimeter = 101 ft3-in x 100-ft . . area = 25 ft2 . . . perimeter = 2001/2 ft1-in x 300-ft . . area = 25 ft2 . . . perimeter = 6001/6 ft0.1-in x 3,000-ft . . area = 25 ft2 . . . perimeter = 6,0001/60 ft

A rectangle measuring (200-ft x 240-ft) has Area = 48,000 square ft Perimeter = 880 ft

perimeter of a square = 4 * root of the area. Perimeter = 4 * root 25 = 4 * 5 = 20 ft

Related questions

It is the sum of its 8 sides added together

A regular octagon is formed from 8 isosceles triangles, each having a base length of 'd' (the length of a side of the octagon) and base angles of 67.5°. The height of one triangle is, 1/2d.tan67.5 The area of one triangle is, 1/2(base x height) = 1/2d.1/2d.tan67.5 = 1/4.d2tan67.5 The area of the octagon = 8 x area of one triangle = 2d2tan 67.5 = 4.8284d2. Thus, 4.8284d2 = 43560 : d2 = 9021.5714 : d = 94.982 The perimeter = 8d = 759.86 ft. (2dp). Note : It can be shown that the area, A = d2(2 + 2√2).

The area of a lot is not enough information to determine its perimeter. The most compact perimeter is approx 740 feet, which is attained by a circular lot. Consider the following rectangular plots, each is of area 1 acre: 100 ft * 435.6ft : perimeter = 1071.2 ft 10 ft * 4356 ft : perimeter = 8732 ft 1 ft * 4356 ft : perimeter = 87122 ft 0.1 ft * 43560 ft : perimeter = 871200.2 ft ... 0.000001 ft * 43,560,000,000 ft : perimeter = 87,120,000,000 ft (approx) = 16,500,000 miles. There is virtually no limit to how much the first dimension can be reduced and the perimeter increased.

An acre is 43560 square feet so any value greater than 740 feet. That perimeter is attained by a circle. But the outside measurement depends on how thin and long the area is: For example, a 100 ft wide x 435.6 ft plot would have a perimeter of 1071.2 ft a 10 ft wide x 4356 ft plot would have a perimeter of 8732 ft a 1 ft wide x 43560 ft plot would have a perimeter of 87122 ft a 0.1 ft wide x 435600 ft plot would have a perimeter of 871200.2 ft There is virtually no limit to how thin and long the plot can be and so no limit to how large the perimeter can be.

12ft

Anywhere from approx 17398.6 ft upwards. The minimum length of fence to enclose 100 acres is when the area is a circle. In which case the length of fence required = circumference of the circle: 1 acre = 43560 sq ft area = π × radius² → radius = √(area ÷ π) length = 2 × π × radius = 2 × π × √(area ÷ π) = 2 × √(area × π) = 2 × √(100 × 43560 sq ft × π) ≈ 7398.5 ft Any other shape with an area of 100 acres will have a longer perimeter; if the shape is a fractal (like the coastline of a country) then the perimeter is infinite.

43560 sq. ft. = 1 acre

It could take near enough forever. A million acres is 43560000000 sq ft. The minimum perimeter for an area of this size is 4*sqrt(43560000000) ft = 4*208710 ft = 834841 ft = 158 miles. But there is no maximum length for the perimeter. The million acres could be 43560 * 1000000 sq ft with a perimeter of 2087120 ft = 395 miles or 4356 *10000000 sq ft with a perimeter of 20008712 ft = 3790 miles or 435.6 * 108 sq ft with a perimeter of 2*108 ft = 37879 miles etc.

perimeter= 42.2 ft area= 108.58 ft squared

The area is not sufficient information to determine the perimeter. First of all, there is no reason to suppose that the area is rectangular as opposed to circular or triangular or some other simple or complicated shape. So, all that can be said is that the perimeter is greater than 178.97 feet, a perimeter that is attained when the area is a circle. If the area is a rectangle, it could be 25.49 ft * 100 ft so that the perimeter is approx 250.98 ft or 2.549 ft * 1000 ft and a perimeter of 2005.10 ft or 0.2549 ft * 10000 ft and a perimeter of 2000.51 ft or 0.0002549 ft * 10000000 ft and a perimeter of 2000000 ft. By making the rectangle thinner and longer, the perimeter can be increased without limit.

perimeter 182 ft. area 1960 square ft.

Not at all.Rectangle A:-- Length = 20-ft, Width = 10-ft.-- Area = 200 square ft-- Perimeter = 60-ftRectangle B:-- Length = 16-ft, Width = 12.5-ft-- Area = 200 square ft-- Perimeter = 57-ftRectangle C:-- Length = 40-ft, Width = 5-ft-- Area = 200 square ft-- Perimeter = 90-ftRectangle D:-- Length = 50-ft, Width = 4-ft-- Area = 200 square ft-- Perimeter = 108-ftRectangle E:-- Length = 100-ft, Width = 2-ft-- Area = 200 square ft-- Perimeter = 204-ftRectangle F:-- Length = 800-ft, Width = 3 inches-- Area = 200 square ft-- Perimeter = 1600-ft 6-in