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To find the perimeter of a shape, you need to know its dimensions and the number of sides. If you are referring to a single side length of ( 2x - 1 ) for a polygon, such as a rectangle, you would need the lengths of the other sides to calculate the perimeter. If it's a square, the perimeter would be ( 4(2x - 1) = 8x - 4 ). Please provide additional details about the shape for a more accurate answer.
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What is the perimeter of the square in terms of x the length of each side is 2x-1in?
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Why does the perimeter of a square double when you double the sides of a square?
The perimeter is the sum of the sides. So if a square has a side of length 1, its perimeter is 1+1+1=1 = 4 If a square has a side doubled to length 2, its perimeter is 2+2+2+2 = 8, or double what it was before. Mathematically, if each side is length x it perimeter is x + x + x = X = 4x If each side is length 2x, its perimeter is 2x +2x+2x+2x = 8x
If a rectangular pentagon has a ide of length 2x 1 what is the perimeter of the pentagon?
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What is the perimeter of the rectangle if the length is 2x 4 and width is 7x-3?
To find the perimeter of a rectangle, you use the formula ( P = 2 \times (\text{length} + \text{width}) ). Given the length is ( 2x + 4 ) and the width is ( 7x - 3 ), the perimeter can be calculated as follows: [ P = 2 \times ((2x + 4) + (7x - 3)) = 2 \times (9x + 1) = 18x + 2. ] Thus, the perimeter of the rectangle is ( 18x + 2 ).
The width of a rectan is 4the perimeter is 105find the length?
Let the length be known as x: 2(x+4) = 105 2x+8 = 105 2x = 105-8 2x = 97 x = 48.5 Length = 48.5 units
What is the perimeter of the square in terms of x the length of each side is 2x-1in?
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Why does the perimeter of a square double when you double the sides of a square?
The perimeter is the sum of the sides. So if a square has a side of length 1, its perimeter is 1+1+1=1 = 4 If a square has a side doubled to length 2, its perimeter is 2+2+2+2 = 8, or double what it was before. Mathematically, if each side is length x it perimeter is x + x + x = X = 4x If each side is length 2x, its perimeter is 2x +2x+2x+2x = 8x
What is the length if the width is 4.2 and the perimeter is 25?
Let the length be x:- 2(x+4.2) = 25 2x+8.4 = 25 2x = 25-8.4 2x = 16.6 x = 8.3 units of length Check:- Perimeter = 8.3+8.3+4.2+4.2 = 25
If a rectangular pentagon has a ide of length 2x 1 what is the perimeter of the pentagon?
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How do you determine the area and perimeter of a rectangle?
for area we should multiple length X breadth for perimeter we should do 2x(LxB)
What is the perimeter of the rectangle if the length is 2x 4 and width is 7x-3?
To find the perimeter of a rectangle, you use the formula ( P = 2 \times (\text{length} + \text{width}) ). Given the length is ( 2x + 4 ) and the width is ( 7x - 3 ), the perimeter can be calculated as follows: [ P = 2 \times ((2x + 4) + (7x - 3)) = 2 \times (9x + 1) = 18x + 2. ] Thus, the perimeter of the rectangle is ( 18x + 2 ).
The perimeter of a length is 122 meters and the length is one more meter than twice the width what is the length?
Let the breadth = xSo, length = 2x+1Thus perimeter will be,2(2x+1+x)=122= 6x+2=122So, 6x=122-2=120So, x= 120/6=20Therefore length=2x+1=2(20)+1=41
The width of a rectan is 4the perimeter is 105find the length?
Let the length be known as x: 2(x+4) = 105 2x+8 = 105 2x = 105-8 2x = 97 x = 48.5 Length = 48.5 units
The perimeter of a retangle is 260 inches the length exceeds the width by 58 inches what would the length and width be?
The perimeter can be written as 2x + 2y = P where the x is length and y is width we know that y = x + 58 so 2y = 2x + 116 2x + 2x + 116 = 260 4x=148 x=37 37+58=95 y=95
The length of a rectangle is twice its width If the perimeter is 84cm what are the dimensions of the rectangle?
Let the length be 2x and the width be x: Perimeter = 2(2x+x) = 84 4x+2x = 84 6x = 84 Divide both sides of the equation by 6 to find the value of x: x = 14 Therefore: length = 28cm and width = 14cm
If Perimeter of a rectangle that has a width of x inches and a length of x plus 16 inches is 2x plus 2x plus 16 inches simplify the expression for the perimeter Find the perimeter if x equals 14?
If the rectangle has a width of x inches, and a length of x + 16 inches, then its perimeter equals to 2x + 2x + 32 or 4x + 32. If x = 14, then x + 16 = 30. So the perimeter of rectangle becomes 2(14) + 2(30) = 28 + 60 = 88 inches.
When the perimeter of a rectangle is 128m the lengeth is 7m than twice the widethfind the length and the wideth?
Let the length be 2x+7 and the width be x: 2(length+width) = perimeter 2(2x+7+x) = 128 4x+14+2x = 128 4x+2x = 128-14 6x = 114 x = 19 Therefore: length = 45m and width = 19m Check: 45+45+19+19 = 128m
