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What is the perpendicular distance from the point 4 -2 to the line 2x -y -5 equals 0?
From the given information the perpendicular line will form an equation of 2y = -x and both simultaneous line equations will intersect each other at (2,-1) and so distance from (4, -2) to (2, -1) is the square root of 5 by using the distance formula.
What else can I help you with?
What is the definition of distance from point to line?
It the point is on the line the distance is 0. If the point is not on the line, then it is possible to draw a unique line from the point to the line which is perpendicular to the line. The distance from the point to the line is the distance along this perpendicular to the line.
What is the perpendicular distance from the point 4 -2 to the straight line of 2x -y -5 equals 0?
Perpendicular equation: x+2y = 0 Point of intersection: (2, -1) Perpendicular distance: square root of 5
What is perpendicular distance?
Perpendicular distance refers to the shortest distance from a point to a line or plane, measured along a line that is perpendicular to that line or plane. This measurement is critical in geometry and various applications, such as determining the distance from a point to a line in analytical geometry. It ensures accuracy in calculations and helps in optimizing designs and analyzing spatial relationships.
What is the shortest distance between a point and a line?
The length of a line segment that starts at the point and is perpendicular to the original line.
What is the perpendicular distance from the point of 7 5 to the straight line whose equation is 3x plus 4y minus 16 equals 0?
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point of intersection: (4, 1) Distance: (7-4)2+(5-1)2 = 25 and the square root of this is the perpendicular distance which is 5 units of measurement
What is the definition of distance from point to line?
It the point is on the line the distance is 0. If the point is not on the line, then it is possible to draw a unique line from the point to the line which is perpendicular to the line. The distance from the point to the line is the distance along this perpendicular to the line.
What is the perpendicular distance from the point 4 -2 to the straight line of 2x -y -5 equals 0?
Perpendicular equation: x+2y = 0 Point of intersection: (2, -1) Perpendicular distance: square root of 5
Which of these is equal to the distance from a point to a line?
the length of a perpendicular segment from the point to the line
The shortest distance form a point to a straight line is?
Its perpendicular distance.
The distance from a point C to the line AB is the length of the segment from C to AB?
That is correct. The distance from a point C to a line AB is the length of the perpendicular segment drawn from point C to line AB. This forms a right angle, creating a right triangle with the segment as the hypotenuse. The length of this perpendicular segment is the shortest distance from the point to the line.
What is the shortest distance between a point and a line?
The length of a line segment that starts at the point and is perpendicular to the original line.
What is the perpendicular ditance from the point 7 5 to the line 3x plus 4y -16 equals 0?
If you mean the perpendicular distance from the coordinate of (7, 5) to the straight line 3x+4y-16 = 0 then it works out as 5 units.
Is the shortest point of a distance measured along the perpendicular segments from the point to the line?
No it is measured from the edge
What is the perpendicular distance from the point of 2 4 to the straight line of y equals 2x plus 10 on the Cartesian plane?
The perpendicular distance from (2, 4) to the equation works out as the square root of 20 or 2 times the square root of 5
When a point is reflected over a horizontal line and is not on the line. Does the y-coordinate stays the same?
No. It changes by double the (perpendicular) distance from the point to the line.
What is the perpendicular distance from the point of 7 5 to the straight line whose equation is 3x plus 4y minus 16 equals 0?
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point of intersection: (4, 1) Distance: (7-4)2+(5-1)2 = 25 and the square root of this is the perpendicular distance which is 5 units of measurement
What is the perpendicular distance from the point 7 and 5 to the straight line equation of 3x plus 4y minus 16 equals 0?
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point: (7, 5) Equations intersect: (4, 1) Perpendicular distance: square root of [(7-4)2+(5-1)2] = 5
