As a straight line equation: y = -3x+b whereas -3 is the slope and b is the y intercept whose value has not been given
It appears to be: y = 2x+3
The equation of the line given is in the form (y = 3x + 5), where the slope is the coefficient of (x). The slope of this line is 3. Since parallel lines have the same slope, the slope of any line parallel to this one would also be 3.
y=3x-3
8
To find the slope of a line perpendicular to the given line, we first need to determine the slope of the line represented by the equation (5x - 15y = 20). Rearranging it into slope-intercept form (y = mx + b), we get (y = \frac{1}{3}x - \frac{4}{3}), which shows that the slope (m) is (\frac{1}{3}). The slope of a line perpendicular to this line is the negative reciprocal, which is (-3).
8
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
If the slope is 2 and the coordinate is (0, 3) then the equation is y = 2x+3
If the slope is 2 and the coordinate is (0, 3) then the equation is y = 2x+3
8
It appears to be: y = 2x+3
if the slope of a line is 2/3, then the slope of a parallel line would be 2/3.
If you mean a slope of 3 and a point of (3, 9) then the equation is y = 3x-3
The equation of the line given is in the form (y = 3x + 5), where the slope is the coefficient of (x). The slope of this line is 3. Since parallel lines have the same slope, the slope of any line parallel to this one would also be 3.
Get in slope intercept form. 3X + 5Y = 15 5Y = -3X + 15 Y = -3/5X + 3 -3/5 is the slope of this line and the line parallel to this line
y-9 = 3(x-4) y = 3x-3 in slope intercept form
y=3x-3