y=3x-3
y=2x+1
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
The equation is: y-2 = 2(x-4) => y = 2x-2
It is: y--5 = -3(x-4) => y = -3x+12-5 => y = -3x+7 in slope-intercept form
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Slope: -3 Point: (4, -5) Equation: y = -3x+7
y=2x+1
y=2x+13
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
The answe iss..... 6
y = 2x - 1
It is: y = 2x-6
y=2x+1
no it is different
y-9 = 3(x-4) y = 3x-3 in slope intercept form
Well. Slope intercept is y= mx + b. With B being the y intercept. If it contains 1,1 and the slope is positive 6, do the equation 1 = 6 (1) + b. 1 = 6 + b -5 = b. So the answer is y = 6x - 5