y=3x-3
y=2x+1
To write the equation in slope-intercept form (y = mx + b), we start with the slope (m) of 2 and the point (3, 7). We can use the point to find the y-intercept (b). Substituting the point into the equation gives us 7 = 2(3) + b, which simplifies to 7 = 6 + b. Thus, b = 1, and the equation in slope-intercept form is y = 2x + 1.
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
The equation is: y-2 = 2(x-4) => y = 2x-2
It is: y--5 = -3(x-4) => y = -3x+12-5 => y = -3x+7 in slope-intercept form
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Slope: -3 Point: (4, -5) Equation: y = -3x+7
y=2x+1
y=2x+13
To write the equation in slope-intercept form (y = mx + b), we start with the slope (m) of 2 and the point (3, 7). We can use the point to find the y-intercept (b). Substituting the point into the equation gives us 7 = 2(3) + b, which simplifies to 7 = 6 + b. Thus, b = 1, and the equation in slope-intercept form is y = 2x + 1.
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
The answe iss..... 6
y = 2x - 1
y=2x+1
It is: y = 2x-6
no it is different
y-9 = 3(x-4) y = 3x-3 in slope intercept form