Line equation: x-2y +12 = 0
Circle equation: x^2 +y^2 -x -31 = 0
Combine both equations together to form: 5y^2 -50y +125 = 0
Divide all terms by 5: y^5 -10y +25 = 0
Factorizing: (y-5)(y-5) = 0 => y = 5
Point of contact by substitution is at: (-2, 5)
area equals pi r squared therefor r squared equals area over pi. Now find square root of r squared and you have "R" (radius) = 2.821
Pi (3.14) times the radius of a circle squared, equals the circumference of a circle.
Combine the equations together and using the quadratic equation formula it works out that the point of contact is at (5/8, 5/2)
Area of a circle equals pi (3.14) times the radius squared.
Area of a circle is: pi times radius squared
area equals pi r squared therefor r squared equals area over pi. Now find square root of r squared and you have "R" (radius) = 2.821
Pi (3.14) times the radius of a circle squared, equals the circumference of a circle.
Combine the equations together and using the quadratic equation formula it works out that the point of contact is at (5/8, 5/2)
If y = 2x +10 and y^2 = 10x then by forming a single quadratic equation and solving it the point of contact is made at (5/8, 5/2)
Area of a circle equals pi (3.14) times the radius squared.
Area of a circle is: pi times radius squared
The graph is a circle with a radius of 6, centered at the origin.
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
Area equals pi times the radius squared.
The graph is a circle with a radius of 6, centered at the origin
They are +/- 5*sqrt(2)
Circle equation: x^2 +y^2 -8x -16y -209 = 0 Completing the squares: (x-4)^2 +(y-8)^2 = 289 Centre of circle: (4, 8) Radius of circle 17 Slope of radius: 0 Perpendicular tangent slope: 0 Tangent point of contact: (21, 8) Tangent equation: x = 21 passing through (21, 0)