There are 1024 different outcomes, so too many to list.
480
If there was any other possible outcome, then the modes are the numbers 7,8, 9 and 10. If there were no other possible outcomes, then there is no mode,
Tossing a coin ten times is a [repeated] experiment or trial. It is neither empirical nor theoretical probability.
The equation ( x^2 = 100 ) has two possible solutions: ( x = 10 ) and ( x = -10 ). This is because squaring both positive and negative values results in the same positive outcome. Thus, the two solutions are ( x = 10 ) and ( x = -10 ).
Cent cent cent cent cent nickel nickel nickel nickel ....,.., not possible
There are 210 total possible outcomes from flipping a coin 10 times.There is one possible outcome where there are 0 heads.There are 10 possible outcomes where there is 1 head.So there are 210 - 11 possible outcomes with at least 2 heads.(1013)
480
252/1024 or 0.246. One method of calculating it is this: The total number of outcomes possible by tossing a coin 10 times is 2 to the 10th, which is 1024. In addition, getting 5 heads in 10 tosses is like arranging 5 identical objects in 10 spaces (the remaining 5 spaces are by default Tails), which can be done in 10C5 ways, which is 252. So the probability of getting 5 heads is 252/1024.
I believe there would be 11 possible outcomes!
If there was any other possible outcome, then the modes are the numbers 7,8, 9 and 10. If there were no other possible outcomes, then there is no mode,
It's a 50/50% chance of that happening (that's just my guess)
3 times (out of 36) is the probablility Possible Outcome 1 - Dice 1: 4, Dice 2: 6 Possible Outcome 2 - Dice 1: 5, Dice 2: 5 Possible Outcome 3 - Dice 1: 6, Dice 2: 4
This is only possible if you allow adding coinsNumber of coins in row x Number of rows = total number of coins5 x 2 = 10 coins4 x 4 = 20 coinsYou would need 10 more coins
10 coins 7 coins and 10 coins
tossing
Their is no possible way to get 75 cents with four coins
2 ones i think.... 50, 10, 10 ,10, 10, 10 or 20, 20, 20, 20, 10, 10