480
If there was any other possible outcome, then the modes are the numbers 7,8, 9 and 10. If there were no other possible outcomes, then there is no mode,
Tossing a coin ten times is a [repeated] experiment or trial. It is neither empirical nor theoretical probability.
Cent cent cent cent cent nickel nickel nickel nickel ....,.., not possible
No. For example, dropping ten coins is not the same thing as picking up 10 coins.
There are 210 total possible outcomes from flipping a coin 10 times.There is one possible outcome where there are 0 heads.There are 10 possible outcomes where there is 1 head.So there are 210 - 11 possible outcomes with at least 2 heads.(1013)
480
252/1024 or 0.246. One method of calculating it is this: The total number of outcomes possible by tossing a coin 10 times is 2 to the 10th, which is 1024. In addition, getting 5 heads in 10 tosses is like arranging 5 identical objects in 10 spaces (the remaining 5 spaces are by default Tails), which can be done in 10C5 ways, which is 252. So the probability of getting 5 heads is 252/1024.
If there was any other possible outcome, then the modes are the numbers 7,8, 9 and 10. If there were no other possible outcomes, then there is no mode,
I believe there would be 11 possible outcomes!
It's a 50/50% chance of that happening (that's just my guess)
3 times (out of 36) is the probablility Possible Outcome 1 - Dice 1: 4, Dice 2: 6 Possible Outcome 2 - Dice 1: 5, Dice 2: 5 Possible Outcome 3 - Dice 1: 6, Dice 2: 4
tossing
This is only possible if you allow adding coinsNumber of coins in row x Number of rows = total number of coins5 x 2 = 10 coins4 x 4 = 20 coinsYou would need 10 more coins
10 coins 7 coins and 10 coins
2 ones i think.... 50, 10, 10 ,10, 10, 10 or 20, 20, 20, 20, 10, 10
Their is no possible way to get 75 cents with four coins