It dependes on the genes of the parent if you have no information of the genes of the parent I cannot tell you
Phenotype: Black Bear x Brown Bear Genotype: BB x bb Possible gametes: B B b b Possible B B crosses: b Bb Bb b Bb Bb Phenotype of offspring: Only Black bears
Given those conditions, the offspring have a 50% chance of demonstrating the dominant phenotype and a 50% chance of demonstrating the recessive phenotype.
100 percent.
Straight thumbs, hitch hiker's thumb is recessive...so the F1 generation in this example would be heterozygous and have the dominant (straight thumbed) phenotype.
If you cross a homozygous dominant individual (AA) with a heterozygous individual (Aa), the offspring will have a genotype ratio of 100% dominant phenotype (AA or Aa) and 0% recessive phenotype (aa). Therefore, if your offspring has a homozygous dominant trait (AA), the likelihood of expressing a recessive trait (aa) is 0%. The Punnett square for this cross would show all dominant traits, confirming that recessive traits cannot be expressed in this scenario.
What percentage of the possible types of offspring had the same phenotype as the parents
75%
What percentage of the possible types of offspring had the same phenotype as the parents
25% The percentage of the possible types of offspring that had the same phenotype as the parents are : bB-bb,BB-Bb=25% has black hair (dad) and 75% has blonde hair (mom).
The phenotype is the physical or observable characteristics of an organism. The phenotype of each parent contributes to the phenotype of the offspring through genetic inheritance. The offspring will exhibit a combination of traits from both parents, resulting in a unique phenotype.
yes
If both parents have the same phenotype, but the offspring did not share that phenotype, then it is likely that the parents have a dominant phenotype, but the offspring has a recessive phenotype, which means that the offpring's genotype would be homozygous recessive, and it's parents' genotypes would be heterozygous. For example, the parents may both have the genotype Bb, which gives them black fur. Approximately 25% of their offspring should have the genotype bb, which gives them the phenotype of white fur.
You look at the offspring. Offspring of a heterogenous match are going to have different phenotype percentages than those of a homogenous match.
The genotype of the offspring that had the same phenotype as the parents is rr or wrinkled. The phenotype for the seed shape of both parent plants is round.
If both parents have the same phenotype, but the offspring did not share that phenotype, then it is likely that the parents have a dominant phenotype, but the offspring has a recessive phenotype, which means that the offpring's genotype would be homozygous recessive, and it's parents' genotypes would be heterozygous. For example, the parents may both have the genotype Bb, which gives them black fur. Approximately 25% of their offspring should have the genotype bb, which gives them the phenotype of white fur.
Phenotype: Black Bear x Brown Bear Genotype: BB x bb Possible gametes: B B b b Possible B B crosses: b Bb Bb b Bb Bb Phenotype of offspring: Only Black bears
A Punnett square shows the possible combinations of alleles from two parents and predicts the likelihood of different phenotypes among their offspring. It provides a visual representation of how genetic traits can be inherited and expressed in an offspring's phenotype.