The power of a motor can be calculated using the formula: Power (P) = Work (W) / Time (t). In this case, the work done is 4000 joules and the time is 20 seconds. Therefore, P = 4000 J / 20 s = 200 watts. Thus, the power of the motor is 200 watts.
The power of a motor can be calculated using the formula ( P = \frac{W}{t} ), where ( P ) is power, ( W ) is work done, and ( t ) is time. Given that the motor does 4500 joules of work in 25 seconds, the power is ( P = \frac{4500 \text{ J}}{25 \text{ s}} = 180 \text{ W} ). Therefore, the power of the small motor is 180 watts.
Calculate the amount of potential energy required. Then divide by the power.
Power input = 700 WEfficiency = 75% so power output = 75% of 700 = 525 W Time = 30 seconds => Work done = 525W * 30s = 15750 W.s = 15750 Joules = 15.75 kiloJoules.
Most likely, the motor can not handle the horse power it needs. Some cars are built to achieve that. But they are cars that are built for racing, or they have more horse power than the average family car.
Power is calculated as energy consumed per unit time. If a bulb uses 3 joules of energy every 10 seconds, its power can be calculated using the formula: Power (in watts) = Energy (in joules) / Time (in seconds). Therefore, the power of the bulb is 3 joules / 10 seconds = 0.3 watts.
The power output would be corralated with the gearing of the motor, but assuming a perfect 1:1 ratio you would have a force of 25lbs, and a power output of 1600 watts.
The power of a motor can be calculated using the formula ( P = \frac{W}{t} ), where ( P ) is power, ( W ) is work done, and ( t ) is time. Given that the motor does 4500 joules of work in 25 seconds, the power is ( P = \frac{4500 \text{ J}}{25 \text{ s}} = 180 \text{ W} ). Therefore, the power of the small motor is 180 watts.
(600 Watts) x (4 minutes) = (600 joules per second) x (240 seconds) = 144,000 joules =144 kilojoules
If it's to lift 30 kg, it depends how far it is to be lifted and how quickly the lift takes to complete. To lift 30 kg through 10 metres requires 30 x 9.8 x 10 joules of energy, that is 3000 Joules. To do that in 10 seconds needs 300 watts, which would be about half a horse power motor. To do it in 5 seconds the power would be 600 watts - a 1 horse power motor.
The amount of energy that a motor transfers every second can be calculated by multiplying the power output of the motor by the time duration over which the power is being exerted. The unit of power is watts (W), and the unit of time is seconds (s). Therefore, the energy transfer per second can be expressed in units of joules per second, which is equivalent to a watt.
To find the time it takes for a 500 W electric motor to do 150,000 J of work, you can use the formula: time = work / power. Substituting the values, time = 150,000 J / 500 W = 300 seconds. Therefore, it would take the motor 300 seconds, or 5 minutes, to do 150,000 J of work.
Calculate the amount of potential energy required. Then divide by the power.
An airplane is a VEHICLE. It's power is provided by a MOTOR.
For a motor's output power to equal its input power, the motor's efficiency must be 100%. As no machine, particularly a rotating machine, can possibly achieve 100% efficiency, there is no condition under which its output power can ever match its input power.
Disconnect wires from motor and check to see if you have power and ground going to motor--if so motor is bad if not have to check wiring and switch to that motor
slip power is a power which is develop by the induced voltage and current in an induction motor
How do you calculate 3ph AC motor power?