Q: What is the probabilit if I throw 4 dice probabiliti that I get all the same numbers on the dice?

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Throw is a very large number of times. If the six numbers come up approximately 1/6 number of times then it is likely that the die (not dice!) is fair. If one or more numbers comes up more often than the die is not fair. You can never be certain.

Eight numbers.

The question is underspecified since the answer depends on the numbers on the dice. If all the numbers on both the dice are the same, there is clearly only one outcome. If the dice have 4 different numbers, then there can be 16 different outcomes. If the numbers on each die are 1,2,3 and 4 (or any four numbers in arithmetic sequence) there will be 7 outcomes.

The first dice can show any of the eight numbers. If the dice are to show different numbers the second dice has 7 different numbers out of a possible 8 to chose from. So the probability is 7/8 or 0.875 or 87.5% chance.

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The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.

1 out of 6 * * * * * Total rubbish. There are 11 possible sums - the numbers 2 to 12. So if you throw the dice 12 times, the first 11 can be different but the 12th must be a repeat.

Throw is a very large number of times. If the six numbers come up approximately 1/6 number of times then it is likely that the die (not dice!) is fair. If one or more numbers comes up more often than the die is not fair. You can never be certain.

(probably but very unlikely) ----------------------------------- A better answer would be as follows. Throw the first dice. It does not matter which number turns up. Let's suppose it was a 2; Now there is only one 2 out of six different numbers when you throw the second dice. So the probability of scoring another 2 is 1 out of 6 = 1/6 Now for each of the results from the two dice which we have read there is only one 2 from the 6 possible numbers, which again means a probability of 1 out of six = 1/6 So the final probability is found by multiplying 1 (certainty) for the first dice by 1/6 for the second dice by 1/6 for the third dice, which = 1/36

There are 3 odd numbers since there are a total of 6 consecutive numbers on a dice. For example, the numbers 1 2 3 4 5 6 are on a dice, so the odd numbers are 1, 3, and 5.