If 10 out of 26 are girls, then the probability of randomly choosing a boy is 16 out of 26, or 8 out of 13, or about 0.6154.
The probability of a boy is still 0.5 no matter how many prior children there are.
Assuming the choices are made randomly and that the chosen people are not returned to the class, the probability is 77/690 = 0.1116 approx.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the required probability is 0.3126.
The 8 possible outcomes for three children are: * ggg * ggb * gbg * gbb * bgg * bgb * bbg * bbb Of these, two girls and a boy occurs 3 out of 8 times, which is a probability of 0.375. This assumes that the probability of a boy and girl being in the family is equal, which is not entirely true for a large number of reasons.
The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.
Probability that a girl is chosen = 23/45 = .511 So, the probability that a boy is chosen = 1 - .511 = .489
The ratio of girls to total students is 15:25, or 3:5. Three out of five students are girls so there would be a 60% probability that a girl would be chosen; a 2 out of 5 chance, or 40% probability that a boy would be chosen.
14/33
The probability of a boy is still 0.5 no matter how many prior children there are.
Assuming the choices are made randomly and that the chosen people are not returned to the class, the probability is 77/690 = 0.1116 approx.
12/27 reduces to 4/9 numerator = the number of acceptable outcomes denominator = total number of outcomes (12 boys + 15 girls)
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the required probability is 0.3126.
4 in 7 chance
The 8 possible outcomes for three children are: * ggg * ggb * gbg * gbb * bgg * bgb * bbg * bbb Of these, two girls and a boy occurs 3 out of 8 times, which is a probability of 0.375. This assumes that the probability of a boy and girl being in the family is equal, which is not entirely true for a large number of reasons.
Yes he does, he has 2 girls and a boy.
The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.
It depends on the context: if you select a child at random from a girls' school, the probability is 0, while if it is at a boys' school it is 1!