12/27 reduces to 4/9
numerator = the number of acceptable outcomes
denominator = total number of outcomes (12 boys + 15 girls)
Probability that a girl is chosen = 23/45 = .511 So, the probability that a boy is chosen = 1 - .511 = .489
If a student is picked at random what is the probability that he/she received an A on his/her fina?
"Playing cards" are chosen at random.
The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.
3/4
Probability that a girl is chosen = 23/45 = .511 So, the probability that a boy is chosen = 1 - .511 = .489
The probability is 15/25 = 3/5
If a student is picked at random what is the probability that he/she received an A on his/her fina?
The probability is 15/25 = 3/5
"Playing cards" are chosen at random.
The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.
3/4
Q. A letter is chosen at random from the word STATistician.What is the probability that it is a vowel?What is the probability that it is T.
To find the probability that the second student chosen is a boy given that the first student chosen is a boy, we first note that there are 22 students total (13 girls and 9 boys). If the first student chosen is a boy, there will then be 8 boys and 13 girls remaining, making a total of 21 students left. Therefore, the probability that the second student is a boy is the number of remaining boys (8) divided by the total remaining students (21), which gives us a probability of ( \frac{8}{21} ).
What the answer
For a single random choice from a standard deck, the probability is 1/13.For a single random choice from a standard deck, the probability is 1/13.For a single random choice from a standard deck, the probability is 1/13.For a single random choice from a standard deck, the probability is 1/13.
The probability that the birthdays of five persons chosen at random will fall in twelve different calender months is zero. You would need at least twelve persons to have a non zero probability.